How can I generate random integers between 0 and 9 (inclusive) in Python?

For example, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

Try:

from random import randrange
print(randrange(10))

More info: http://docs.python.org/library/random.html#random.randrange

import random
print(random.randint(0,9))

random.randint(a, b)

Return a random integer N such that a <= N <= b.

Docs: https://docs.python.org/3.1/library/random.html#random.randint

Try this:

from random import randrange, uniform

# randrange gives you an integral value
irand = randrange(0, 10)

# uniform gives you a floating-point value
frand = uniform(0, 10)

from random import randint

x = [randint(0, 9) for p in range(0, 10)]

This generates 10 pseudorandom integers in range 0 to 9 inclusive.

The secrets module is new in Python 3.6. This is better than the random module for cryptography or security uses.

To randomly print an integer in the inclusive range 0-9:

from secrets import randbelow
print(randbelow(10))

For details, see PEP 506.

Choose the size of the array (in this example, I have chosen the size to be 20). And then, use the following:

import numpy as np   
np.random.randint(10, size=(1, 20))

You can expect to see an output of the following form (different random integers will be returned each time you run it; hence you can expect the integers in the output array to differ from the example given below).

array([[1, 6, 1, 2, 8, 6, 3, 3, 2, 5, 6, 5, 0, 9, 5, 6, 4, 5, 9, 3]])

Try this through random.shuffle

>>> import random
>>> nums = range(10)
>>> random.shuffle(nums)
>>> nums
[6, 3, 5, 4, 0, 1, 2, 9, 8, 7]

I would try one of the following:

1.> numpy.random.randint

import numpy as np
X1 = np.random.randint(low=0, high=10, size=(15,))

print (X1)
>>> array([3, 0, 9, 0, 5, 7, 6, 9, 6, 7, 9, 6, 6, 9, 8])

2.> numpy.random.uniform

import numpy as np
X2 = np.random.uniform(low=0, high=10, size=(15,)).astype(int)

print (X2)
>>> array([8, 3, 6, 9, 1, 0, 3, 6, 3, 3, 1, 2, 4, 0, 4])

3.> random.randrange

from random import randrange
X3 = [randrange(10) for i in range(15)]

print (X3)
>>> [2, 1, 4, 1, 2, 8, 8, 6, 4, 1, 0, 5, 8, 3, 5]

4.> random.randint

from random import randint
X4 = [randint(0, 9) for i in range(0, 15)]

print (X4)
>>> [6, 2, 6, 9, 5, 3, 2, 3, 3, 4, 4, 7, 4, 9, 6]

Speed:

► np.random.randint is the fastest, followed by np.random.uniform and random.randrange. random.randint is the slowest.

► Both np.random.randint and np.random.uniform are much faster (~8 – 12 times faster) than random.randrange and random.randint .

%timeit np.random.randint(low=0, high=10, size=(15,))
>> 1.64 µs ± 7.83 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

%timeit np.random.uniform(low=0, high=10, size=(15,)).astype(int)
>> 2.15 µs ± 38.6 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)

%timeit [randrange(10) for i in range(15)]
>> 12.9 µs ± 60.4 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)

%timeit [randint(0, 9) for i in range(0, 15)]
>> 20 µs ± 386 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)

Notes:

1.> np.random.randint generates random integers over the half-open interval [low, high).

2.> np.random.uniform generates uniformly distributed numbers over the half-open interval [low, high).

3.> random.randrange(stop) generates a random number from range(start, stop, step).

4.> random.randint(a, b) returns a random integer N such that a <= N <= b.

5.> astype(int) casts the numpy array to int data type.

6.> I have chosen size = (15,). This will give you a numpy array of length = 15.

In case of continuous numbers randint or randrange are probably the best choices but if you have several distinct values in a sequence (i.e. a list) you could also use choice:

>>> import random
>>> values = list(range(10))
>>> random.choice(values)
5

choice also works for one item from a not-continuous sample:

>>> values = [1, 2, 3, 5, 7, 10]
>>> random.choice(values)
7

If you need it “cryptographically strong” there’s also a secrets.choice in python 3.6 and newer:

>>> import secrets
>>> values = list(range(10))
>>> secrets.choice(values)
2

While many posts demonstrate how to get one random integer, the original question asks how to generate random integers (plural):

How can I generate random integers between 0 and 9 (inclusive) in Python?

For clarity, here we demonstrate how to get multiple random integers.

Given

>>> import random


lo = 0
hi = 10
size = 5

Code

Multiple, Random Integers

# A
>>> [lo + int(random.random() * (hi - lo)) for _ in range(size)]
[5, 6, 1, 3, 0]

# B
>>> [random.randint(lo, hi) for _ in range(size)]
[9, 7, 0, 7, 3]

# C
>>> [random.randrange(lo, hi) for _ in range(size)]
[8, 3, 6, 8, 7]

# D
>>> lst = list(range(lo, hi))
>>> random.shuffle(lst)
>>> [lst[i] for i in range(size)]
[6, 8, 2, 5, 1]

# E
>>> [random.choice(range(lo, hi)) for _ in range(size)]
[2, 1, 6, 9, 5]

Sample of Random Integers

# F
>>> random.choices(range(lo, hi), k=size)
[3, 2, 0, 8, 2]

# G
>>> random.sample(range(lo, hi), k=size)
[4, 5, 1, 2, 3]

Details

Some posts demonstrate how to natively generate multiple random integers.¹ Here are some options that address the implied question:

• A: random.random returns a random float in the range [0.0, 1.0)
• B: random.randint returns a random integer N such that a <= N <= b
• C: random.randrange alias to randint(a, b+1)
• D: random.shuffle shuffles a sequence in place
• E: random.choice returns a random element from the non-empty sequence
• F: random.choices returns k selections from a population (with replacement, Python 3.6+)
• G: random.sample returns k unique selections from a population (without replacement):²

See also R. Hettinger’s talk on Chunking and Aliasing using examples from the random module.

Here is a comparison of some random functions in the Standard Library and Numpy:

| | random                | numpy.random                     |
|-|-----------------------|----------------------------------|
|A| random()              | random()                         |
|B| randint(low, high)    | randint(low, high)               |
|C| randrange(low, high)  | randint(low, high)               |
|D| shuffle(seq)          | shuffle(seq)                     |
|E| choice(seq)           | choice(seq)                      |
|F| choices(seq, k)       | choice(seq, size)                |
|G| sample(seq, k)        | choice(seq, size, replace=False) |

You can also quickly convert one of many distributions in Numpy to a sample of random integers.³

Examples

>>> np.random.normal(loc=5, scale=10, size=size).astype(int)
array([17, 10,  3,  1, 16])

>>> np.random.poisson(lam=1, size=size).astype(int)
array([1, 3, 0, 2, 0])

>>> np.random.lognormal(mean=0.0, sigma=1.0, size=size).astype(int)
array([1, 3, 1, 5, 1])

_{¹Namely @John Lawrence Aspden, @S T Mohammed, @SiddTheKid, @user14372, @zangw, et al. ²@prashanth mentions this module showing one integer. ³Demonstrated by @Siddharth Satpathy}

if you want to use numpy then use the following:

import numpy as np
print(np.random.randint(0,10))

>>> import random
>>> random.randrange(10)
3
>>> random.randrange(10)
1

To get a list of ten samples:

>>> [random.randrange(10) for x in range(10)]
[9, 0, 4, 0, 5, 7, 4, 3, 6, 8]

Generating random integers between 0 and 9.

import numpy
X = numpy.random.randint(0, 10, size=10)
print(X)

Output:

[4 8 0 4 9 6 9 9 0 7]

random.sample is another that can be used

import random
n = 1 # specify the no. of numbers
num = random.sample(range(10),  n)
num[0] # is the required number

Best way is to use import Random function

import random
print(random.sample(range(10), 10))

or without any library import:

n={} 
for i in range(10):
    n[i]=i

for p in range(10):
    print(n.popitem()[1])

here the popitems removes and returns an arbitrary value from the dictionary n.

This is more of a mathematical approach but it works 100% of the time:

Let’s say you want to use random.random() function to generate a number between a and b. To achieve this, just do the following:

num = (b-a)*random.random() + a;

Of course, you can generate more numbers.

From the documentation page for the random module:

Warning: The pseudo-random generators of this module should not be used for security purposes. Use os.urandom() or SystemRandom if you require a cryptographically secure pseudo-random number generator.

random.SystemRandom, which was introduced in Python 2.4, is considered cryptographically secure. It is still available in Python 3.7.1 which is current at time of writing.

>>> import string
>>> string.digits
'0123456789'
>>> import random
>>> random.SystemRandom().choice(string.digits)
'8'
>>> random.SystemRandom().choice(string.digits)
'1'
>>> random.SystemRandom().choice(string.digits)
'8'
>>> random.SystemRandom().choice(string.digits)
'5'

Instead of string.digits, range could be used per some of the other answers along perhaps with a comprehension. Mix and match according to your needs.

OpenTURNS allows to not only simulate the random integers but also to define the associated distribution with the UserDefined defined class.

The following simulates 12 outcomes of the distribution.

import openturns as ot
points = [[i] for i in range(10)]
distribution = ot.UserDefined(points) # By default, with equal weights.
for i in range(12):
    x = distribution.getRealization()
    print(i,x)

This prints:

0 [8]
1 [7]
2 [4]
3 [7]
4 [3]
5 [3]
6 [2]
7 [9]
8 [0]
9 [5]
10 [9]
11 [6]

The brackets are there becausex is a Point in 1-dimension. It would be easier to generate the 12 outcomes in a single call to getSample:

sample = distribution.getSample(12)

would produce:

>>> print(sample)
     [ v0 ]
 0 : [ 3  ]
 1 : [ 9  ]
 2 : [ 6  ]
 3 : [ 3  ]
 4 : [ 2  ]
 5 : [ 6  ]
 6 : [ 9  ]
 7 : [ 5  ]
 8 : [ 9  ]
 9 : [ 5  ]
10 : [ 3  ]
11 : [ 2  ]

More details on this topic are here: http://openturns.github.io/openturns/master/user_manual/_generated/openturns.UserDefined.html

I had better luck with this for Python 3.6

str_Key = ""                                                                                                
str_RandomKey = ""                                                                                          
for int_I in range(128):                                                                                    
      str_Key = random.choice('0123456789')
      str_RandomKey = str_RandomKey + str_Key 

Just add characters like ‘ABCD’ and ‘abcd’ or ‘^!~=-><‘ to alter the character pool to pull from, change the range to alter the number of characters generated.