I have the following folder structure.

application/app/folder/file.py

and I want to import some functions from file.py in another Python file which resides in

application/app2/some_folder/some_file.py

I’ve tried

from application.app.folder.file import func_name

and some other various attempts but so far I couldn’t manage to import properly. How can I do this?

By default, you can’t. When importing a file, Python only searches the current directory, the directory that the entry-point script is running from, and sys.path which includes locations such as the package installation directory (it’s actually a little more complex than this, but this covers most cases).

However, you can add to the Python path at runtime:

# some_file.py
import sys
# insert at 1, 0 is the script path (or '' in REPL)
sys.path.insert(1, '/path/to/application/app/folder')

import file

Nothing wrong with:

from application.app.folder.file import func_name

Just make sure folder also contains an __init__.py, this allows it to be included as a package. Not sure why the other answers talk about PYTHONPATH.

When modules are in parallel locations, as in the question:

application/app2/some_folder/some_file.py
application/app2/another_folder/another_file.py

This shorthand makes one module visible to the other:

import sys
sys.path.append('../')

First import sys in name-file.py

 import sys

Second append the folder path in name-file.py

sys.path.insert(0, '/the/folder/path/name-package/')

Third Make a blank file called __ init __.py in your subdirectory (this tells Python it is a package)

• name-file.py
• name-package
  • __ init __.py
  • name-module.py

Fourth import the module inside the folder in name-file.py

from name-package import name-module

I think an ad-hoc way would be to use the environment variable PYTHONPATH as described in the documentation: Python2, Python3

# Linux & OSX
export PYTHONPATH=$HOME/dirWithScripts/:$PYTHONPATH

# Windows
set PYTHONPATH=C:\path\to\dirWithScripts\;%PYTHONPATH%

The answers here are lacking in clarity, this is tested on Python 3.6

With this folder structure:

main.py
|
---- myfolder/myfile.py

Where myfile.py has the content:

def myfunc():
    print('hello')

The import statement in main.py is:

from myfolder.myfile import myfunc
myfunc()

and this will print hello.

Your problem is that Python is looking in the Python directory for this file and not finding it. You must specify that you are talking about the directory that you are in and not the Python one.

To do this you change this:

from application.app.folder.file import func_name

to this:

from .application.app.folder.file import func_name

By adding the dot you are saying look in this folder for the application folder instead of looking in the Python directory.

From what I know, add an __init__.py file directly in the folder of the functions you want to import will do the job.

In Python 3.4 and later, you can import from a source file directly (link to documentation). This is not the simplest solution, but I’m including this answer for completeness.

Here is an example. First, the file to be imported, named foo.py:

def announce():
    print("Imported!")

The code that imports the file above, inspired heavily by the example in the documentation:

import importlib.util

def module_from_file(module_name, file_path):
    spec = importlib.util.spec_from_file_location(module_name, file_path)
    module = importlib.util.module_from_spec(spec)
    spec.loader.exec_module(module)
    return module

foo = module_from_file("foo", "/path/to/foo.py")

if __name__ == "__main__":
    print(foo)
    print(dir(foo))
    foo.announce()

The output:

<module 'foo' from '/path/to/foo.py'>
['__builtins__', '__cached__', '__doc__', '__file__', '__loader__', '__name__', '__package__', '__spec__', 'announce']
Imported!

Note that the variable name, the module name, and the filename need not match. This code still works:

import importlib.util

def module_from_file(module_name, file_path):
    spec = importlib.util.spec_from_file_location(module_name, file_path)
    module = importlib.util.module_from_spec(spec)
    spec.loader.exec_module(module)
    return module

baz = module_from_file("bar", "/path/to/foo.py")

if __name__ == "__main__":
    print(baz)
    print(dir(baz))
    baz.announce()

The output:

<module 'bar' from '/path/to/foo.py'>
['__builtins__', '__cached__', '__doc__', '__file__', '__loader__', '__name__', '__package__', '__spec__', 'announce']
Imported!

Programmatically importing modules was introduced in Python 3.1 and gives you more control over how modules are imported. Refer to the documentation for more information.

Worked for me in python3 on linux

import sys  
sys.path.append(pathToFolderContainingScripts)  
from scriptName import functionName #scriptName without .py extension  

Try Python’s relative imports:

from ...app.folder.file import func_name

Every leading dot is another higher level in the hierarchy beginning with the current directory.

Problems? If this isn’t working for you then you probably are getting bit by the many gotcha’s relative imports has. Read answers and comments for more details: How to fix “Attempted relative import in non-package” even with __init__.py

Hint: have __init__.py at every directory level. You might need python -m application.app2.some_folder.some_file (leaving off .py) which you run from the top level directory or have that top level directory in your PYTHONPATH. Phew!

I was faced with the same challenge, especially when importing multiple files, this is how I managed to overcome it.

import os, sys

from os.path import dirname, join, abspath
sys.path.insert(0, abspath(join(dirname(__file__), '..')))

from root_folder import file_name

Considering application as the root directory for your python project, create an empty __init__.py file in application, app and folder folders. Then in your some_file.py make changes as follows to get the definition of func_name:

import sys
sys.path.insert(0, r'/from/root/directory/application')

from application.app.folder.file import func_name ## You can also use '*' wildcard to import all the functions in file.py file.
func_name()

Using sys.path.append with an absolute path is not ideal when moving the application to other environments. Using a relative path won’t always work because the current working directory depends on how the script was invoked.

Since the application folder structure is fixed, we can use os.path to get the full path of the module we wish to import. For example, if this is the structure:

/home/me/application/app2/some_folder/vanilla.py
/home/me/application/app2/another_folder/mango.py

And let’s say that you want to import the “mango” module. You could do the following in vanilla.py:

import sys, os.path
mango_dir = (os.path.abspath(os.path.join(os.path.dirname(__file__), '..'))
+ '/another_folder/')
sys.path.append(mango_dir)
import mango

Of course, you don’t need the mango_dir variable.

To understand how this works look at this interactive session example:

>>> import os
>>> mydir = '/home/me/application/app2/some_folder'
>>> newdir = os.path.abspath(os.path.join(mydir, '..'))
>>> newdir
    '/home/me/application/app2'
>>> newdir = os.path.abspath(os.path.join(mydir, '..')) + '/another_folder'
>>> 
>>> newdir
'/home/me/application/app2/another_folder'
>>> 

And check the os.path documentation.

This works for me on windows

# some_file.py on mainApp/app2 
import sys
sys.path.insert(0, sys.path[0]+'\\app2')

import some_file

I’m quite special : I use Python with Windows !

I just complete information : for both Windows and Linux, both relative and absolute path work into sys.path (I need relative paths because I use my scripts on the several PCs and under different main directories).

And when using Windows both \ and / can be used as separator for file names and of course you must double \ into Python strings,
some valid examples :

sys.path.append('c:\\tools\\mydir')
sys.path.append('..\\mytools')
sys.path.append('c:/tools/mydir')
sys.path.append('../mytools')

(note : I think that / is more convenient than \, event if it is less ‘Windows-native’ because it is Linux-compatible and simpler to write and copy to Windows explorer)

If the purpose of loading a module from a specific path is to assist you during the development of a custom module, you can create a symbolic link in the same folder of the test script that points to the root of the custom module. This module reference will take precedence over any other modules installed of the same name for any script run in that folder.

I tested this on Linux but it should work in any modern OS that supports symbolic links.

One advantage to this approach is that you can you can point to a module that’s sitting in your own local SVC branch working copy which can greatly simplify the development cycle time and reduce failure modes of managing different versions of the module.

In my case I had a class to import. My file looked like this:

# /opt/path/to/code/log_helper.py
class LogHelper:
    # stuff here

In my main file I included the code via:

import sys
sys.path.append("/opt/path/to/code/")
from log_helper import LogHelper

I bumped into the same question several times, so I would like to share my solution.

Python Version: 3.X

The following solution is for someone who develops your application in Python version 3.X because Python 2 is not supported since Jan/1/2020.

Project Structure

In python 3, you don’t need __init__.py in your project subdirectory due to the Implicit Namespace Packages. See Is init.py not required for packages in Python 3.3+

Project 
├── main.py
├── .gitignore
|
├── a
|   └── file_a.py
|
└── b
    └── file_b.py

Problem Statement

In file_b.py, I would like to import a class A in file_a.py under the folder a.

Solutions

#1 A quick but dirty way

Without installing the package like you are currently developing a new project

Using the try catch to check if the errors. Code example:

import sys
try:
    # The insertion index should be 1 because index 0 is this file
    sys.path.insert(1, '/absolute/path/to/folder/a')  # the type of path is string
    # because the system path already have the absolute path to folder a
    # so it can recognize file_a.py while searching 
    from file_a import A
except (ModuleNotFoundError, ImportError) as e:
    print("{} fileure".format(type(e)))
else:
    print("Import succeeded")

#2 Install your package

Once you installed your application (in this post, the tutorial of installation is not included)

You can simply

try:
    from __future__ import absolute_import
    # now it can reach class A of file_a.py in folder a 
    # by relative import
    from ..a.file_a import A  
except (ModuleNotFoundError, ImportError) as e:
    print("{} fileure".format(type(e)))
else:
    print("Import succeeded")

Happy coding!

I was working on project a that I wanted users to install via pip install a with the following file list:

.
├── setup.py
├── MANIFEST.in
└── a
    ├── __init__.py
    ├── a.py
    └── b
        ├── __init__.py
        └── b.py

setup.py

from setuptools import setup

setup (
  name='a',
  version='0.0.1',
  packages=['a'],
  package_data={
    'a': ['b/*'],
  },
)

MANIFEST.in

recursive-include b *.*

a/init.py

from __future__ import absolute_import

from a.a import cats
import a.b

a/a.py

cats = 0

a/b/init.py

from __future__ import absolute_import

from a.b.b import dogs

a/b/b.py

dogs = 1

I installed the module by running the following from the directory with MANIFEST.in:

python setup.py install

Then, from a totally different location on my filesystem /moustache/armwrestle I was able to run:

import a
dir(a)

Which confirmed that a.cats indeed equalled 0 and a.b.dogs indeed equalled 1, as intended.

Instead of just doing an import ..., do this :

from <MySubFolder> import <MyFile>

MyFile is inside the MySubFolder.

You can refresh the Python shell by pressing f5, or go to Run-> Run Module. This way you don’t have to change the directory to read something from the file. Python will automatically change the directory. But if you want to work with different files from different directory in the Python Shell, then you can change the directory in sys, as Cameron said earlier.

So I had just right clicked on my IDE, and added a new folder and was wondering why I wasn’t able to import from it. Later I realized I have to right click and create a Python Package, and not a classic file system folder. Or a post-mortem method being adding an __init__.py (which makes python treat the file system folder as a package) as mentioned in other answers. Adding this answer here just in case someone went this route.

You can use importlib to import modules where you want to import a module from a folder using a string like so:

import importlib

scriptName = 'Snake'

script = importlib.import_module('Scripts\\.%s' % scriptName)

This example has a main.py which is the above code then a folder called Scripts and then you can call whatever you need from this folder by changing the scriptName variable. You can then use script to reference to this module. such as if I have a function called Hello() in the Snake module you can run this function by doing so:

script.Hello()

I have tested this in Python 3.6

I’ve had these problems a number of times. I’ve come to this same page a lot. In my last problem I had to run the server from a fixed directory, but whenever debugging I wanted to run from different sub-directories.

import sys
sys.insert(1, /path) 

did NOT work for me because at different modules I had to read different *.csv files which were all in the same directory.

In the end, what worked for me was not pythonic, I guess, but:

I used a if __main__ on top of the module I wanted to debug, that is run from a different than usual path.

So:

# On top of the module, instead of on the bottom
import os
if __name__ == '__main__':
    os.chdir('/path/for/the/regularly/run/directory')