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使用Python请求发布JSON

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问题：使用Python请求发布JSON
回答 0
回答 1
回答 2
回答 3
回答 4
回答 5

问题：使用Python请求发布JSON

我需要将JSON从客户端发布到服务器。我正在使用Python 2.7.1和simplejson。客户端正在使用请求。服务器是CherryPy。我可以从服务器获取硬编码的JSON（代码未显示），但是当我尝试将JSON POST到服务器时，会收到“ 400 Bad Request”。

这是我的客户代码：

data = {'sender':   'Alice',
    'receiver': 'Bob',
    'message':  'We did it!'}
data_json = simplejson.dumps(data)
payload = {'json_payload': data_json}
r = requests.post("http://localhost:8080", data=payload)

这是服务器代码。

class Root(object):

    def __init__(self, content):
        self.content = content
        print self.content  # this works

    exposed = True

    def GET(self):
        cherrypy.response.headers['Content-Type'] = 'application/json'
        return simplejson.dumps(self.content)

    def POST(self):
        self.content = simplejson.loads(cherrypy.request.body.read())

有任何想法吗？

点击查看英文原文

I need to POST a JSON from a client to a server. I’m using Python 2.7.1 and simplejson. The client is using Requests. The server is CherryPy. I can GET a hard-coded JSON from the server (code not shown), but when I try to POST a JSON to the server, I get “400 Bad Request”.

Here is my client code:

data = {'sender':   'Alice',
    'receiver': 'Bob',
    'message':  'We did it!'}
data_json = simplejson.dumps(data)
payload = {'json_payload': data_json}
r = requests.post("http://localhost:8080", data=payload)

Here is the server code.

class Root(object):

    def __init__(self, content):
        self.content = content
        print self.content  # this works

    exposed = True

    def GET(self):
        cherrypy.response.headers['Content-Type'] = 'application/json'
        return simplejson.dumps(self.content)

    def POST(self):
        self.content = simplejson.loads(cherrypy.request.body.read())

Any ideas?

回答 0

从Requests 2.4.2及更高版本开始，您可以在调用中使用’json’参数，从而使其更简单。

>>> import requests
>>> r = requests.post('http://httpbin.org/post', json={"key": "value"})
>>> r.status_code
200
>>> r.json()
{'args': {},
 'data': '{"key": "value"}',
 'files': {},
 'form': {},
 'headers': {'Accept': '*/*',
             'Accept-Encoding': 'gzip, deflate',
             'Connection': 'close',
             'Content-Length': '16',
             'Content-Type': 'application/json',
             'Host': 'httpbin.org',
             'User-Agent': 'python-requests/2.4.3 CPython/3.4.0',
             'X-Request-Id': 'xx-xx-xx'},
 'json': {'key': 'value'},
 'origin': 'x.x.x.x',
 'url': 'http://httpbin.org/post'}

编辑：此功能已添加到官方文档中。您可以在这里查看：请求文档

点击查看英文原文

As of Requests version 2.4.2 and onwards, you can alternatively use ‘json’ parameter in the call which makes it simpler.

>>> import requests
>>> r = requests.post('http://httpbin.org/post', json={"key": "value"})
>>> r.status_code
200
>>> r.json()
{'args': {},
 'data': '{"key": "value"}',
 'files': {},
 'form': {},
 'headers': {'Accept': '*/*',
             'Accept-Encoding': 'gzip, deflate',
             'Connection': 'close',
             'Content-Length': '16',
             'Content-Type': 'application/json',
             'Host': 'httpbin.org',
             'User-Agent': 'python-requests/2.4.3 CPython/3.4.0',
             'X-Request-Id': 'xx-xx-xx'},
 'json': {'key': 'value'},
 'origin': 'x.x.x.x',
 'url': 'http://httpbin.org/post'}

EDIT: This feature has been added to the official documentation. You can view it here: Requests documentation

回答 1

原来我缺少标题信息。以下作品：

url = "http://localhost:8080"
data = {'sender': 'Alice', 'receiver': 'Bob', 'message': 'We did it!'}
headers = {'Content-type': 'application/json', 'Accept': 'text/plain'}
r = requests.post(url, data=json.dumps(data), headers=headers)
点击查看英文原文

It turns out I was missing the header information. The following works:

url = "http://localhost:8080"
data = {'sender': 'Alice', 'receiver': 'Bob', 'message': 'We did it!'}
headers = {'Content-type': 'application/json', 'Accept': 'text/plain'}
r = requests.post(url, data=json.dumps(data), headers=headers)

回答 2

从请求2.4.2（https://pypi.python.org/pypi/requests）开始，支持“ json”参数。无需指定“ Content-Type”。因此，较短的版本：

requests.post('http://httpbin.org/post', json={'test': 'cheers'})
点击查看英文原文

From requests 2.4.2 (https://pypi.python.org/pypi/requests), the “json” parameter is supported. No need to specify “Content-Type”. So the shorter version:

requests.post('http://httpbin.org/post', json={'test': 'cheers'})

回答 3

更好的方法是：

url = "http://xxx.xxxx.xx"

datas = {"cardno":"6248889874650987","systemIdentify":"s08","sourceChannel": 12}

headers = {'Content-type': 'application/json'}

rsp = requests.post(url, json=datas, headers=headers)
点击查看英文原文

The better way is：

url = "http://xxx.xxxx.xx"

datas = {"cardno":"6248889874650987","systemIdentify":"s08","sourceChannel": 12}

headers = {'Content-type': 'application/json'}

rsp = requests.post(url, json=datas, headers=headers)

回答 4

与python 3.5+完美搭配

客户：

import requests
data = {'sender':   'Alice',
    'receiver': 'Bob',
    'message':  'We did it!'}
r = requests.post("http://localhost:8080", json={'json_payload': data})

服务器：

class Root(object):

    def __init__(self, content):
        self.content = content
        print self.content  # this works

    exposed = True

    def GET(self):
        cherrypy.response.headers['Content-Type'] = 'application/json'
        return simplejson.dumps(self.content)

    @cherrypy.tools.json_in()
    @cherrypy.tools.json_out()
    def POST(self):
        self.content = cherrypy.request.json
        return {'status': 'success', 'message': 'updated'}
点击查看英文原文

Works perfectly with python 3.5+

client:

import requests
data = {'sender':   'Alice',
    'receiver': 'Bob',
    'message':  'We did it!'}
r = requests.post("http://localhost:8080", json={'json_payload': data})

server:

class Root(object):

    def __init__(self, content):
        self.content = content
        print self.content  # this works

    exposed = True

    def GET(self):
        cherrypy.response.headers['Content-Type'] = 'application/json'
        return simplejson.dumps(self.content)

    @cherrypy.tools.json_in()
    @cherrypy.tools.json_out()
    def POST(self):
        self.content = cherrypy.request.json
        return {'status': 'success', 'message': 'updated'}

回答 5

应该使用（data / json / files）之间的哪个参数，它实际上取决于名为ContentType的请求标头（通常通过浏览器的开发人员工具进行检查），

当Content-Type为application / x-www-form-urlencoded时，代码应为：

requests.post(url, data=jsonObj)

当Content-Type为application / json时，您的代码应为以下之一：

requests.post(url, json=jsonObj)
requests.post(url, data=jsonstr, headers={"Content-Type":"application/json"})

当Content-Type为multipart / form-data时，它用于上传文件，因此您的代码应为：

requests.post(url, files=xxxx)
点击查看英文原文

Which parameter between (data / json / files) should be used,it’s actually depends on a request header named ContentType(usually check this through developer tools of your browser),

when the Content-Type is application/x-www-form-urlencoded, code should be:

requests.post(url, data=jsonObj)

when the Content-Type is application/json, your code is supposed to be one of below:

requests.post(url, json=jsonObj)

requests.post(url, data=jsonstr, headers={"Content-Type":"application/json"})

when the Content-Type is multipart/form-data, it’s used to upload files, so your code should be:

requests.post(url, files=xxxx)