问题:分配熊猫数据框列dtypes
我想在中设置dtype
多列的s pd.Dataframe
(我有一个文件必须手动解析为列表列表,因为该文件不适合pd.read_csv
)
import pandas as pd
print pd.DataFrame([['a','1'],['b','2']],
dtype={'x':'object','y':'int'},
columns=['x','y'])
我懂了
ValueError: entry not a 2- or 3- tuple
我可以设置它们的唯一方法是循环遍历每个列变量并使用进行重铸astype
。
dtypes = {'x':'object','y':'int'}
mydata = pd.DataFrame([['a','1'],['b','2']],
columns=['x','y'])
for c in mydata.columns:
mydata[c] = mydata[c].astype(dtypes[c])
print mydata['y'].dtype #=> int64
有没有更好的办法?
I want to set the dtype
s of multiple columns in pd.Dataframe
(I have a file that I’ve had to manually parse into a list of lists, as the file was not amenable for pd.read_csv
)
import pandas as pd
print pd.DataFrame([['a','1'],['b','2']],
dtype={'x':'object','y':'int'},
columns=['x','y'])
I get
ValueError: entry not a 2- or 3- tuple
The only way I can set them is by looping through each column variable and recasting with astype
.
dtypes = {'x':'object','y':'int'}
mydata = pd.DataFrame([['a','1'],['b','2']],
columns=['x','y'])
for c in mydata.columns:
mydata[c] = mydata[c].astype(dtypes[c])
print mydata['y'].dtype #=> int64
Is there a better way?
回答 0
从0.17开始,您必须使用显式转换:
pd.to_datetime, pd.to_timedelta and pd.to_numeric
(如下所述,convert_objects
在0.17中已不再弃用“魔术” )
df = pd.DataFrame({'x': {0: 'a', 1: 'b'}, 'y': {0: '1', 1: '2'}, 'z': {0: '2018-05-01', 1: '2018-05-02'}})
df.dtypes
x object
y object
z object
dtype: object
df
x y z
0 a 1 2018-05-01
1 b 2 2018-05-02
您可以将它们应用于要转换的每一列:
df["y"] = pd.to_numeric(df["y"])
df["z"] = pd.to_datetime(df["z"])
df
x y z
0 a 1 2018-05-01
1 b 2 2018-05-02
df.dtypes
x object
y int64
z datetime64[ns]
dtype: object
并确认dtype已更新。
大熊猫0.12-0.16的旧/建议答案:您可以convert_objects
用来推断更好的dtypes:
In [21]: df
Out[21]:
x y
0 a 1
1 b 2
In [22]: df.dtypes
Out[22]:
x object
y object
dtype: object
In [23]: df.convert_objects(convert_numeric=True)
Out[23]:
x y
0 a 1
1 b 2
In [24]: df.convert_objects(convert_numeric=True).dtypes
Out[24]:
x object
y int64
dtype: object
魔法!(遗憾地看到它过时了。)
Since 0.17, you have to use the explicit conversions:
pd.to_datetime, pd.to_timedelta and pd.to_numeric
(As mentioned below, no more “magic”, convert_objects
has been deprecated in 0.17)
df = pd.DataFrame({'x': {0: 'a', 1: 'b'}, 'y': {0: '1', 1: '2'}, 'z': {0: '2018-05-01', 1: '2018-05-02'}})
df.dtypes
x object
y object
z object
dtype: object
df
x y z
0 a 1 2018-05-01
1 b 2 2018-05-02
You can apply these to each column you want to convert:
df["y"] = pd.to_numeric(df["y"])
df["z"] = pd.to_datetime(df["z"])
df
x y z
0 a 1 2018-05-01
1 b 2 2018-05-02
df.dtypes
x object
y int64
z datetime64[ns]
dtype: object
and confirm the dtype is updated.
OLD/DEPRECATED ANSWER for pandas 0.12 – 0.16: You can use convert_objects
to infer better dtypes:
In [21]: df
Out[21]:
x y
0 a 1
1 b 2
In [22]: df.dtypes
Out[22]:
x object
y object
dtype: object
In [23]: df.convert_objects(convert_numeric=True)
Out[23]:
x y
0 a 1
1 b 2
In [24]: df.convert_objects(convert_numeric=True).dtypes
Out[24]:
x object
y int64
dtype: object
Magic! (Sad to see it deprecated.)
回答 1
对于那些来自Google(例如我)的人:
convert_objects
从0.17开始不推荐使用-如果您使用它,则会收到类似以下的警告:
FutureWarning: convert_objects is deprecated. Use the data-type specific converters
pd.to_datetime, pd.to_timedelta and pd.to_numeric.
您应该执行以下操作:
For those coming from Google (etc.) such as myself:
convert_objects
has been deprecated since 0.17 – if you use it, you get a warning like this one:
FutureWarning: convert_objects is deprecated. Use the data-type specific converters
pd.to_datetime, pd.to_timedelta and pd.to_numeric.
You should do something like the following:
回答 2
您可以使用pandas显式设置类型,DataFrame.astype(dtype, copy=True, raise_on_error=True, **kwargs)
并使用想要的dtypes传递字典dtype
这是一个例子:
import pandas as pd
wheel_number = 5
car_name = 'jeep'
minutes_spent = 4.5
# set the columns
data_columns = ['wheel_number', 'car_name', 'minutes_spent']
# create an empty dataframe
data_df = pd.DataFrame(columns = data_columns)
df_temp = pd.DataFrame([[wheel_number, car_name, minutes_spent]],columns = data_columns)
data_df = data_df.append(df_temp, ignore_index=True)
In [11]: data_df.dtypes
Out[11]:
wheel_number float64
car_name object
minutes_spent float64
dtype: object
data_df = data_df.astype(dtype= {"wheel_number":"int64",
"car_name":"object","minutes_spent":"float64"})
现在您可以看到它已更改
In [18]: data_df.dtypes
Out[18]:
wheel_number int64
car_name object
minutes_spent float64
you can set the types explicitly with pandas DataFrame.astype(dtype, copy=True, raise_on_error=True, **kwargs)
and pass in a dictionary with the dtypes you want to dtype
here’s an example:
import pandas as pd
wheel_number = 5
car_name = 'jeep'
minutes_spent = 4.5
# set the columns
data_columns = ['wheel_number', 'car_name', 'minutes_spent']
# create an empty dataframe
data_df = pd.DataFrame(columns = data_columns)
df_temp = pd.DataFrame([[wheel_number, car_name, minutes_spent]],columns = data_columns)
data_df = data_df.append(df_temp, ignore_index=True)
In [11]: data_df.dtypes
Out[11]:
wheel_number float64
car_name object
minutes_spent float64
dtype: object
data_df = data_df.astype(dtype= {"wheel_number":"int64",
"car_name":"object","minutes_spent":"float64"})
now you can see that it’s changed
In [18]: data_df.dtypes
Out[18]:
wheel_number int64
car_name object
minutes_spent float64
回答 3
设置列类型的另一种方法是,首先使用所需的类型构造一个numpy记录数组,将其填充,然后将其传递给DataFrame构造函数。
import pandas as pd
import numpy as np
x = np.empty((10,), dtype=[('x', np.uint8), ('y', np.float64)])
df = pd.DataFrame(x)
df.dtypes ->
x uint8
y float64
Another way to set the column types is to first construct a numpy record array with your desired types, fill it out and then pass it to a DataFrame constructor.
import pandas as pd
import numpy as np
x = np.empty((10,), dtype=[('x', np.uint8), ('y', np.float64)])
df = pd.DataFrame(x)
df.dtypes ->
x uint8
y float64
回答 4
面临类似的问题。在我的情况下,我需要手动解析来自Cisco日志的1000个文件。
为了灵活处理字段和类型,我已经使用StringIO + read_cvs成功地进行了测试,它确实接受dtype规范的要求。
我通常将每个文件(5k-20k行)放入缓冲区并动态创建dtype字典。
最终,我将这些数据帧连接(通过分类…感谢0.19)到一个大数据帧中,然后将其转储到hdf5中。
这些东西
import pandas as pd
import io
output = io.StringIO()
output.write('A,1,20,31\n')
output.write('B,2,21,32\n')
output.write('C,3,22,33\n')
output.write('D,4,23,34\n')
output.seek(0)
df=pd.read_csv(output, header=None,
names=["A","B","C","D"],
dtype={"A":"category","B":"float32","C":"int32","D":"float64"},
sep=","
)
df.info()
<class 'pandas.core.frame.DataFrame'>
RangeIndex: 5 entries, 0 to 4
Data columns (total 4 columns):
A 5 non-null category
B 5 non-null float32
C 5 non-null int32
D 5 non-null float64
dtypes: category(1), float32(1), float64(1), int32(1)
memory usage: 205.0 bytes
None
不是很pythonic ….但是能胜任
希望能帮助到你。
杰西
facing similar problem to you. In my case I have 1000’s of files from cisco logs that I need to parse manually.
In order to be flexible with fields and types I have successfully tested using StringIO + read_cvs which indeed does accept a dict for the dtype specification.
I usually get each of the files ( 5k-20k lines) into a buffer and create the dtype dictionaries dynamically.
Eventually I concatenate ( with categorical… thanks to 0.19) these dataframes into a large data frame that I dump into hdf5.
Something along these lines
import pandas as pd
import io
output = io.StringIO()
output.write('A,1,20,31\n')
output.write('B,2,21,32\n')
output.write('C,3,22,33\n')
output.write('D,4,23,34\n')
output.seek(0)
df=pd.read_csv(output, header=None,
names=["A","B","C","D"],
dtype={"A":"category","B":"float32","C":"int32","D":"float64"},
sep=","
)
df.info()
<class 'pandas.core.frame.DataFrame'>
RangeIndex: 5 entries, 0 to 4
Data columns (total 4 columns):
A 5 non-null category
B 5 non-null float32
C 5 non-null int32
D 5 non-null float64
dtypes: category(1), float32(1), float64(1), int32(1)
memory usage: 205.0 bytes
None
Not very pythonic…. but does the job
Hope it helps.
JC
回答 5
最好使用键入的np.arrays,然后将数据和列名作为字典传递。
import numpy as np
import pandas as pd
# Feature: np arrays are 1: efficient, 2: can be pre-sized
x = np.array(['a', 'b'], dtype=object)
y = np.array([ 1 , 2 ], dtype=np.int32)
df = pd.DataFrame({
'x' : x, # Feature: column name is near data array
'y' : y,
}
)
You’re better off using typed np.arrays, and then pass the data and column names as a dictionary.
import numpy as np
import pandas as pd
# Feature: np arrays are 1: efficient, 2: can be pre-sized
x = np.array(['a', 'b'], dtype=object)
y = np.array([ 1 , 2 ], dtype=np.int32)
df = pd.DataFrame({
'x' : x, # Feature: column name is near data array
'y' : y,
}
)