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问题：列表到数组的转换以使用ravel（）函数

我在python中有一个列表，我想将其转换为数组以能够使用ravel()函数。

I have a list in python and I want to convert it to an array to be able to use ravel() function.

回答 0

import numpy as np
myarray = np.asarray(mylist)

import numpy as np
myarray = np.asarray(mylist)

from array import array
listA = list(range(0,50))
for item in listA:
    print(item)
arrayA = array("i", listA)
for item in arrayA:
    print(item)

from array import array
listA = list(range(0,50))
for item in listA:
    print(item)
arrayA = array("i", listA)
for item in arrayA:
    print(item)

我想要一种无需使用额外模块即可执行此操作的方法。首先将列表转换为字符串，然后追加到数组：

dataset_list = ''.join(input_list)
dataset_array = []
for item in dataset_list.split(';'): # comma, or other
    dataset_array.append(item)

I wanted a way to do this without using an extra module. First turn list to string, then append to an array:

dataset_list = ''.join(input_list)
dataset_array = []
for item in dataset_list.split(';'): # comma, or other
    dataset_array.append(item)

如果您只想ravel在自己的（嵌套，我要摆姿势？）列表上打电话，则可以直接执行此操作，numpy将为您进行转换：

L = [[1,None,3],["The", "quick", object]]
np.ravel(L)
# array([1, None, 3, 'The', 'quick', <class 'object'>], dtype=object)

If all you want is calling ravel on your (nested, I s’pose?) list, you can do that directly, numpy will do the casting for you:

L = [[1,None,3],["The", "quick", object]]
np.ravel(L)
# array([1, None, 3, 'The', 'quick', <class 'object'>], dtype=object)

使用以下代码：

import numpy as np

myArray=np.array([1,2,4])  #func used to convert [1,2,3] list into an array
print(myArray)

Use the following code:

import numpy as np

myArray=np.array([1,2,4])  #func used to convert [1,2,3] list into an array
print(myArray)

如果变量b有一个列表，则只需执行以下操作：

创建一个新变量“ a”为：a=[] 然后将列表分配给“ a”为：a=b

现在“ a”在数组中具有列表“ b”的所有组件。

因此您已成功将列表转换为数组。

if variable b has a list then you can simply do the below:

create a new variable “a” as: a=[] then assign the list to “a” as: a=b

now “a” has all the components of list “b” in array.

so you have successfully converted list to array.