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删除matplotlib图中的xticks？

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问题：删除matplotlib图中的xticks？
回答 0
回答 1
回答 2
回答 3
回答 4
回答 5
回答 6
回答 7
回答 8

问题：删除matplotlib图中的xticks？

我有一个Semilogx图，我想删除xticks。我试过了：

plt.gca().set_xticks([])
plt.xticks([])
ax.set_xticks([])

网格消失（确定），但仍保留小刻度线（在主刻度线的位置）。如何删除它们？

点击查看英文原文

I have a semilogx plot and I would like to remove the xticks. I tried:

plt.gca().set_xticks([])
plt.xticks([])
ax.set_xticks([])

The grid disappears (ok), but small ticks (at the place of the main ticks) remain. How to remove them?

回答 0

该tick_params方法对于这样的事情非常有用。此代码关闭主要和次要刻度线，并从x轴删除标签。

from matplotlib import pyplot as plt
plt.plot(range(10))
plt.tick_params(
    axis='x',          # changes apply to the x-axis
    which='both',      # both major and minor ticks are affected
    bottom=False,      # ticks along the bottom edge are off
    top=False,         # ticks along the top edge are off
    labelbottom=False) # labels along the bottom edge are off
plt.show()
plt.savefig('plot')
plt.clf()

点击查看英文原文

The tick_params method is very useful for stuff like this. This code turns off major and minor ticks and removes the labels from the x-axis.

from matplotlib import pyplot as plt
plt.plot(range(10))
plt.tick_params(
    axis='x',          # changes apply to the x-axis
    which='both',      # both major and minor ticks are affected
    bottom=False,      # ticks along the bottom edge are off
    top=False,         # ticks along the top edge are off
    labelbottom=False) # labels along the bottom edge are off
plt.show()
plt.savefig('plot')
plt.clf()

回答 1

不完全是OP的要求，但是禁用所有轴线，刻度和标签的简单方法是简单地调用：

plt.axis('off')
点击查看英文原文

Not exactly what the OP was asking for, but a simple way to disable all axes lines, ticks and labels is to simply call:

plt.axis('off')

回答 2

另外，您可以传递一个空的刻度位置并将其标记为

# for matplotlib.pyplot
# ---------------------
plt.xticks([], [])
# for axis object
# ---------------
# from Anakhand May 5 at 13:08
# for major ticks
ax.set_xticks([])
# for minor ticks
ax.set_xticks([], minor=True)
点击查看英文原文

Alternatively, you can pass an empty tick position and label as

# for matplotlib.pyplot
# ---------------------
plt.xticks([], [])
# for axis object
# ---------------
# from Anakhand May 5 at 13:08
# for major ticks
ax.set_xticks([])
# for minor ticks
ax.set_xticks([], minor=True)

回答 3

这是我在matplotlib邮件列表中找到的替代解决方案：

import matplotlib.pylab as plt

x = range(1000)
ax = plt.axes()
ax.semilogx(x, x)
ax.xaxis.set_ticks_position('none')

点击查看英文原文

Here is an alternative solution that I found on the matplotlib mailing list:

import matplotlib.pylab as plt

x = range(1000)
ax = plt.axes()
ax.semilogx(x, x)
ax.xaxis.set_ticks_position('none')

回答 4

有比John Vinyard提供的解决方案更好，更简单的解决方案。用途NullLocator：

import matplotlib.pyplot as plt

plt.plot(range(10))
plt.gca().xaxis.set_major_locator(plt.NullLocator())
plt.show()
plt.savefig('plot')

希望能有所帮助。

点击查看英文原文

There is a better, and simpler, solution than the one given by John Vinyard. Use NullLocator:

import matplotlib.pyplot as plt

plt.plot(range(10))
plt.gca().xaxis.set_major_locator(plt.NullLocator())
plt.show()
plt.savefig('plot')

Hope that helps.

回答 5

尝试删除标签（但不删除刻度）：

import matplotlib.pyplot as plt

plt.setp( ax.get_xticklabels(), visible=False)

例

点击查看英文原文

Try this to remove the labels (but not the ticks):

import matplotlib.pyplot as plt

plt.setp( ax.get_xticklabels(), visible=False)

example

回答 6

此代码片段可能仅有助于删除xtick。

from matplotlib import pyplot as plt    
plt.xticks([])

此代码片段可能有助于同时删除xtick和yticks。

from matplotlib import pyplot as plt    
plt.xticks([]),plt.yticks([])
点击查看英文原文

This snippet might help in removing the xticks only.

from matplotlib import pyplot as plt    
plt.xticks([])

This snippet might help in removing the xticks and yticks both.

from matplotlib import pyplot as plt    
plt.xticks([]),plt.yticks([])

回答 7

# remove all the ticks (both axes), and tick labels on the Y axis
plt.tick_params(top='off', bottom='off', left='off', right='off', labelleft='off', labelbottom='on')
点击查看英文原文 
# remove all the ticks (both axes), and tick labels on the Y axis
plt.tick_params(top='off', bottom='off', left='off', right='off', labelleft='off', labelbottom='on')

回答 8

那些正在寻找一个简短的命令来关闭所有刻度线和标签的人应该可以

plt.tick_params(top=False, bottom=False, left=False, right=False, labelleft=False, labelbottom=False)

bool从版本matplotlib> = 2.1.1开始，允许输入各个参数

对于自定义刻度线设置，文档非常有用：

https://matplotlib.org/api/_as_gen/matplotlib.axes.Axes.tick_params.html

点击查看英文原文

Those of you looking for a short command to switch off all ticks and labels should be fine with

plt.tick_params(top=False, bottom=False, left=False, right=False,
                labelleft=False, labelbottom=False)

which allows type bool for respective parameters since version matplotlib>=2.1.1

For custom tick settings, the docs are helpful:

https://matplotlib.org/api/_as_gen/matplotlib.axes.Axes.tick_params.html