Using numpy, how can I do the following:

ln(x)

Is it equivalent to:

np.log(x)

I apologise for such a seemingly trivial question, but my understanding of the difference between log and ln is that ln is logspace e?

np.log is ln, whereas np.log10 is your standard base 10 log.

Relevant documentation:

http://docs.scipy.org/doc/numpy/reference/generated/numpy.log.html

http://docs.scipy.org/doc/numpy/reference/generated/numpy.log10.html

Correct, np.log(x) is the Natural Log (base e log) of x.

For other bases, remember this law of logs: log-b(x) = log-k(x) / log-k(b) where log-b is the log in some arbitrary base b, and log-k is the log in base k, e.g.

here k = e

l = np.log(x) / np.log(100)

and l is the log-base-100 of x

I usually do like this:

from numpy import log as ln

Perhaps this can make you more comfortable.

You could simple just do the reverse by making the base of log to e.

import math

e = 2.718281

math.log(e, 10) = 2.302585093
ln(10) = 2.30258093

from numpy.lib.scimath import logn
from math import e

#using: x - var
logn(e, x)