在Python中生成随机字母

问题:在Python中生成随机字母

有没有一种方法可以在Python中生成随机字母(如random.randint,但用于字母)?random.randint的范围功能会很好,但是拥有仅输出随机字母的生成器总比没有好。

Is there a way to generate random letters in Python (like random.randint but for letters)? The range functionality of random.randint would be nice but having a generator that just outputs a random letter would be better than nothing.


回答 0

简单:

>>> import string
>>> string.ascii_letters
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
>>> import random
>>> random.choice(string.ascii_letters)
'j'

string.ascii_letters 根据当前语言环境返回包含小写字母和大写字母的字符串。

random.choice 从序列中返回单个随机元素。

Simple:

>>> import string
>>> string.ascii_letters
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
>>> import random
>>> random.choice(string.ascii_letters)
'j'

string.ascii_letters returns a string containing the lower case and upper case letters according to the current locale.

random.choice returns a single, random element from a sequence.


回答 1

>>> import random
>>> import string
>>> random.choice(string.ascii_letters)
'g'
>>> import random
>>> import string
>>> random.choice(string.ascii_letters)
'g'

回答 2

>>>def random_char(y):
       return ''.join(random.choice(string.ascii_letters) for x in range(y))

>>>print (random_char(5))
>>>fxkea

生成y个随机字符

>>>def random_char(y):
       return ''.join(random.choice(string.ascii_letters) for x in range(y))

>>>print (random_char(5))
>>>fxkea

to generate y number of random characters


回答 3

>>> import random
>>> import string    
>>> random.choice(string.ascii_lowercase)
'b'
>>> import random
>>> import string    
>>> random.choice(string.ascii_lowercase)
'b'

回答 4

完整性的另一种方式:

>>> chr(random.randrange(97, 97 + 26))

利用事实 ascii “ a”为97,并且字母表中有26个字母。

确定random.randrange()函数调用的上限和下限时,请记住它random.randrange()在上限上是互斥的,这意味着它只会生成比提供的值小1个单位的整数。

Another way, for completeness:

>>> chr(random.randrange(97, 97 + 26))

Use the fact that ascii ‘a’ is 97, and there are 26 letters in the alphabet.

When determining the upper and lower bound of the random.randrange() function call, remember that random.randrange() is exclusive on its upper bound, meaning it will only ever generate an integer up to 1 unit less that the provided value.


回答 5

您可以使用它来获得一个或多个随机字母

import random
import string
random.seed(10)
letters = string.ascii_lowercase
rand_letters = random.choices(letters,k=5) # where k is the number of required rand_letters

print(rand_letters)

['o', 'l', 'p', 'f', 'v']

You can use this to get one or more random letter(s)

import random
import string
random.seed(10)
letters = string.ascii_lowercase
rand_letters = random.choices(letters,k=5) # where k is the number of required rand_letters

print(rand_letters)

['o', 'l', 'p', 'f', 'v']

回答 6

您可以列出一个清单:

import random
list1=['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
b=random.randint(0,7)
print(list1[b])

You can just make a list:

import random
list1=['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
b=random.randint(0,7)
print(list1[b])

回答 7

def randchar(a, b):
    return chr(random.randint(ord(a), ord(b)))
def randchar(a, b):
    return chr(random.randint(ord(a), ord(b)))

回答 8

import random
def guess_letter():
    return random.choice('abcdefghijklmnopqrstuvwxyz')
import random
def guess_letter():
    return random.choice('abcdefghijklmnopqrstuvwxyz')

回答 9

import random
def Random_Alpha():
    l = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
    return l[random.randint(0,25)]

print(Random_Alpha())
import random
def Random_Alpha():
    l = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
    return l[random.randint(0,25)]

print(Random_Alpha())

回答 10

您可以使用

map(lambda a : chr(a),  np.random.randint(low=65, high=90, size=4))

You can use

map(lambda a : chr(a),  np.random.randint(low=65, high=90, size=4))

回答 11

import string
import random

KEY_LEN = 20

def base_str():
    return (string.letters+string.digits)   
def key_gen():
    keylist = [random.choice(base_str()) for i in range(KEY_LEN)]
    return ("".join(keylist))

您可以这样获得随机字符串:

g9CtUljUWD9wtk1z07iF
ndPbI1DDn6UvHSQoDMtd
klMFY3pTYNVWsNJ6cs34
Qgr7OEalfhXllcFDGh2l
import string
import random

KEY_LEN = 20

def base_str():
    return (string.letters+string.digits)   
def key_gen():
    keylist = [random.choice(base_str()) for i in range(KEY_LEN)]
    return ("".join(keylist))

You can get random strings like this:

g9CtUljUWD9wtk1z07iF
ndPbI1DDn6UvHSQoDMtd
klMFY3pTYNVWsNJ6cs34
Qgr7OEalfhXllcFDGh2l

回答 12

def create_key(key_len):
    key = ''
    valid_characters_list = string.letters + string.digits
    for i in range(key_len):
        character = choice(valid_characters_list)
        key = key + character
    return key

def create_key_list(key_num):
    keys = []
    for i in range(key_num):
        key = create_key(key_len)
        if key not in keys:
            keys.append(key)
    return keys
def create_key(key_len):
    key = ''
    valid_characters_list = string.letters + string.digits
    for i in range(key_len):
        character = choice(valid_characters_list)
        key = key + character
    return key

def create_key_list(key_num):
    keys = []
    for i in range(key_num):
        key = create_key(key_len)
        if key not in keys:
            keys.append(key)
    return keys

回答 13

以前的所有答案都是正确的,如果您要查找各种类型的随机字符(即字母数字和特殊字符),那么这是我创建的一个脚本,用于演示创建随机函数的各种类型,它具有三个函数,一个用于数字,字符和特殊字符。该脚本仅生成密码,仅是演示生成随机字符的各种方式的示例。

import string
import random
import sys

#make sure it's 3.7 or above
print(sys.version)

def create_str(str_length):
    return random.sample(string.ascii_letters, str_length)

def create_num(num_length):
    digits = []
    for i in range(num_length):
        digits.append(str(random.randint(1, 100)))

    return digits

def create_special_chars(special_length):
    stringSpecial = []
    for i in range(special_length):
        stringSpecial.append(random.choice('!$%&()*+,-.:;<=>?@[]^_`{|}~'))

    return stringSpecial

print("how many characters would you like to use ? (DO NOT USE LESS THAN 8)")
str_cnt = input()
print("how many digits would you like to use ? (DO NOT USE LESS THAN 2)")
num_cnt = input()
print("how many special characters would you like to use ? (DO NOT USE LESS THAN 1)")
s_chars_cnt = input()
password_values = create_str(int(str_cnt)) +create_num(int(num_cnt)) + create_special_chars(int(s_chars_cnt))

#shuffle/mix the values
random.shuffle(password_values)

print("generated password is: ")
print(''.join(password_values))

结果:

All previous answers are correct, if you are looking for random characters of various types (i.e. alphanumeric and special characters) then here is an script that I created to demonstrate various types of creating random functions, it has three functions one for numbers, alpha- characters and special characters. The script simply generates passwords and is just an example to demonstrate various ways of generating random characters.

import string
import random
import sys

#make sure it's 3.7 or above
print(sys.version)

def create_str(str_length):
    return random.sample(string.ascii_letters, str_length)

def create_num(num_length):
    digits = []
    for i in range(num_length):
        digits.append(str(random.randint(1, 100)))

    return digits

def create_special_chars(special_length):
    stringSpecial = []
    for i in range(special_length):
        stringSpecial.append(random.choice('!$%&()*+,-.:;<=>?@[]^_`{|}~'))

    return stringSpecial

print("how many characters would you like to use ? (DO NOT USE LESS THAN 8)")
str_cnt = input()
print("how many digits would you like to use ? (DO NOT USE LESS THAN 2)")
num_cnt = input()
print("how many special characters would you like to use ? (DO NOT USE LESS THAN 1)")
s_chars_cnt = input()
password_values = create_str(int(str_cnt)) +create_num(int(num_cnt)) + create_special_chars(int(s_chars_cnt))

#shuffle/mix the values
random.shuffle(password_values)

print("generated password is: ")
print(''.join(password_values))

Result:


回答 14

好吧,这就是我的答案!它运作良好。只需将所需的随机字母数放入“数字” …(Python 3)

import random

def key_gen():
    keylist = random.choice('abcdefghijklmnopqrstuvwxyz')
    return keylist

number = 0
list_item = ''
while number < 20:
    number = number + 1
    list_item = list_item + key_gen()

print(list_item)

well, this is my answer! It works well. Just put the number of random letters you want in ‘number’… (Python 3)

import random

def key_gen():
    keylist = random.choice('abcdefghijklmnopqrstuvwxyz')
    return keylist

number = 0
list_item = ''
while number < 20:
    number = number + 1
    list_item = list_item + key_gen()

print(list_item)

回答 15

import string
import random

def random_char(y):
    return ''.join(random.choice(string.ascii_letters+string.digits+li) for x in range(y))
no=int(input("Enter the number of character for your password=  "))
li = random.choice('!@#$%^*&( )_+}{')
print(random_char(no)+li)
import string
import random

def random_char(y):
    return ''.join(random.choice(string.ascii_letters+string.digits+li) for x in range(y))
no=int(input("Enter the number of character for your password=  "))
li = random.choice('!@#$%^*&( )_+}{')
print(random_char(no)+li)

回答 16

我的代码过于复杂:

import random

letter = (random.randint(1,26))
if letter == 1:
   print ('a')
elif letter == 2:
    print ('b')
elif letter == 3:
    print ('c')
elif letter == 4:
    print ('d')
elif letter == 5:
    print ('e')
elif letter == 6:
    print ('f')
elif letter == 7:
    print ('g')
elif letter == 8:
    print ('h')
elif letter == 9:
    print ('i')
elif letter == 10:
    print ('j')
elif letter == 11:
    print ('k')
elif letter == 12:
    print ('l')
elif letter == 13:
    print ('m')
elif letter == 14:
    print ('n')
elif letter == 15:
    print ('o')
elif letter == 16:
    print ('p')
elif letter == 17:
    print ('q')
elif letter == 18:
    print ('r')
elif letter == 19:
    print ('s')
elif letter == 20:
    print ('t')
elif letter == 21:
    print ('u')
elif letter == 22:
    print ('v')
elif letter == 23:
    print ('w')
elif letter == 24:
    print ('x')
elif letter == 25:
    print ('y')
elif letter == 26:
    print ('z')

它基本上会从26个随机数中生成一个,然后转换为相应的字母。可以改进它,但是我只是一个初学者,我为这段代码感到自豪。

My overly complicated piece of code:

import random

letter = (random.randint(1,26))
if letter == 1:
   print ('a')
elif letter == 2:
    print ('b')
elif letter == 3:
    print ('c')
elif letter == 4:
    print ('d')
elif letter == 5:
    print ('e')
elif letter == 6:
    print ('f')
elif letter == 7:
    print ('g')
elif letter == 8:
    print ('h')
elif letter == 9:
    print ('i')
elif letter == 10:
    print ('j')
elif letter == 11:
    print ('k')
elif letter == 12:
    print ('l')
elif letter == 13:
    print ('m')
elif letter == 14:
    print ('n')
elif letter == 15:
    print ('o')
elif letter == 16:
    print ('p')
elif letter == 17:
    print ('q')
elif letter == 18:
    print ('r')
elif letter == 19:
    print ('s')
elif letter == 20:
    print ('t')
elif letter == 21:
    print ('u')
elif letter == 22:
    print ('v')
elif letter == 23:
    print ('w')
elif letter == 24:
    print ('x')
elif letter == 25:
    print ('y')
elif letter == 26:
    print ('z')

It basically generates a random number out of 26 and then converts into its corresponding letter. This could defiantly be improved but I am only a beginner and I am proud of this piece of code.


回答 17

也许这可以帮助您:

import random
for a in range(64,90):
    h = random.randint(64, a)
    e += chr(h)
print e

Maybe this can help you:

import random
for a in range(64,90):
    h = random.randint(64, a)
    e += chr(h)
print e

回答 18

在键盘上放一个python,让他翻动字母,直到找到自己喜欢的随机组合。

import string #This was a design above but failed to print. I remodled it.
import random
irandom = random.choice(string.ascii_letters) 
print irandom

Place a python on the keyboard and let him roll over the letters until you find your preferd random combo Just kidding!

import string #This was a design above but failed to print. I remodled it.
import random
irandom = random.choice(string.ascii_letters) 
print irandom