问题:如何在Python中获取字符串的子字符串?
有没有一种方法可以在Python中为字符串加上字符串,以从第三个字符到字符串的末尾获取新的字符串?
也许喜欢myString[2:end]
吗?
如果离开第二部分意味着“直到最后”,而如果离开第一部分,它是否从头开始?
Is there a way to substring a string in Python, to get a new string from the third character to the end of the string?
Maybe like myString[2:end]
?
If leaving the second part means ’till the end’, and if you leave the first part, does it start from the start?
回答 0
>>> x = "Hello World!"
>>> x[2:]
'llo World!'
>>> x[:2]
'He'
>>> x[:-2]
'Hello Worl'
>>> x[-2:]
'd!'
>>> x[2:-2]
'llo Worl'
Python称这个概念为“切片”,它不仅适用于字符串,还适用于更多的领域。看看这里的一个全面的介绍。
>>> x = "Hello World!"
>>> x[2:]
'llo World!'
>>> x[:2]
'He'
>>> x[:-2]
'Hello Worl'
>>> x[-2:]
'd!'
>>> x[2:-2]
'llo Worl'
Python calls this concept “slicing” and it works on more than just strings. Take a look here for a comprehensive introduction.
回答 1
只是为了完整性,没有其他人提到过它。数组切片的第三个参数是一个步骤。因此,反转字符串很简单:
some_string[::-1]
或选择其他字符为:
"H-e-l-l-o- -W-o-r-l-d"[::2] # outputs "Hello World"
在字符串中前进和后退的能力保持了从头到尾排列切片的一致性。
Just for completeness as nobody else has mentioned it. The third parameter to an array slice is a step. So reversing a string is as simple as:
some_string[::-1]
Or selecting alternate characters would be:
"H-e-l-l-o- -W-o-r-l-d"[::2] # outputs "Hello World"
The ability to step forwards and backwards through the string maintains consistency with being able to array slice from the start or end.
回答 2
Substr()通常(即PHP和Perl)以这种方式工作:
s = Substr(s, beginning, LENGTH)
因此参数为beginning
和LENGTH
。
但是Python的行为是不同的。它期望从开始到结束(!)。初学者很难发现这一点。因此,正确替换Substr(s,Beginning,LENGTH)是
s = s[ beginning : beginning + LENGTH]
Substr() normally (i.e. PHP and Perl) works this way:
s = Substr(s, beginning, LENGTH)
So the parameters are beginning
and LENGTH
.
But Python’s behaviour is different; it expects beginning and one after END (!). This is difficult to spot by beginners. So the correct replacement for Substr(s, beginning, LENGTH) is
s = s[ beginning : beginning + LENGTH]
回答 3
实现此目的的一种常见方法是通过字符串切片。
MyString[a:b]
给您一个从索引a到(b-1)的子字符串。
A common way to achieve this is by string slicing.
MyString[a:b]
gives you a substring from index a to (b – 1).
回答 4
这里似乎缺少一个示例:完整(浅)副本。
>>> x = "Hello World!"
>>> x
'Hello World!'
>>> x[:]
'Hello World!'
>>> x==x[:]
True
>>>
这是用于创建序列类型(而非插入字符串)的副本的常见用法[:]
。浅表复制列表,请参阅无明显原因的Python列表切片语法。
One example seems to be missing here: full (shallow) copy.
>>> x = "Hello World!"
>>> x
'Hello World!'
>>> x[:]
'Hello World!'
>>> x==x[:]
True
>>>
This is a common idiom for creating a copy of sequence types (not of interned strings), [:]
. Shallow copies a list, see Python list slice syntax used for no obvious reason.
回答 5
有没有一种方法可以在Python中为字符串加上字符串,以从第3个字符到字符串的末尾获取新的字符串?
也许喜欢myString[2:end]
吗?
是的,如果您将名称()分配或绑定end
到常量单例,这实际上是可行的None
:
>>> end = None
>>> myString = '1234567890'
>>> myString[2:end]
'34567890'
切片符号具有3个重要参数:
如果未指定,则默认为None
-但我们可以显式传递它们:
>>> stop = step = None
>>> start = 2
>>> myString[start:stop:step]
'34567890'
如果离开第二部分意味着“直到最后”,那么如果离开第一部分,它是否从头开始?
是的,例如:
>>> start = None
>>> stop = 2
>>> myString[start:stop:step]
'12'
请注意,我们在切片中包括了开始,但是我们仅上至(不包括)停止。
当step为时None
,默认情况下切片将1
用于该步骤。如果您使用负整数执行操作,则Python足够聪明,可以从头到尾进行操作。
>>> myString[::-1]
'0987654321'
我在对“解释切片符号问题”的回答中会详细解释切片符号。
Is there a way to substring a string in Python, to get a new string from the 3rd character to the end of the string?
Maybe like myString[2:end]
?
Yes, this actually works if you assign, or bind, the name,end
, to constant singleton, None
:
>>> end = None
>>> myString = '1234567890'
>>> myString[2:end]
'34567890'
Slice notation has 3 important arguments:
Their defaults when not given are None
– but we can pass them explicitly:
>>> stop = step = None
>>> start = 2
>>> myString[start:stop:step]
'34567890'
If leaving the second part means ’till the end’, if you leave the first part, does it start from the start?
Yes, for example:
>>> start = None
>>> stop = 2
>>> myString[start:stop:step]
'12'
Note that we include start in the slice, but we only go up to, and not including, stop.
When step is None
, by default the slice uses 1
for the step. If you step with a negative integer, Python is smart enough to go from the end to the beginning.
>>> myString[::-1]
'0987654321'
I explain slice notation in great detail in my answer to Explain slice notation Question.
回答 6
除了“结束”之外,您已经准备就绪。这称为切片符号。您的示例应为:
new_sub_string = myString[2:]
如果省略第二个参数,则它隐式为字符串的结尾。
You’ve got it right there except for “end”. It’s called slice notation. Your example should read:
new_sub_string = myString[2:]
If you leave out the second parameter it is implicitly the end of the string.
回答 7
我想在讨论中添加两点:
您可以None
改为在空白处使用“从头开始”或“到末尾”来指定:
'abcde'[2:None] == 'abcde'[2:] == 'cde'
这在不能提供空格作为参数的函数中特别有用:
def substring(s, start, end):
"""Remove `start` characters from the beginning and `end`
characters from the end of string `s`.
Examples
--------
>>> substring('abcde', 0, 3)
'abc'
>>> substring('abcde', 1, None)
'bcde'
"""
return s[start:end]
Python具有切片对象:
idx = slice(2, None)
'abcde'[idx] == 'abcde'[2:] == 'cde'
I would like to add two points to the discussion:
You can use None
instead on an empty space to specify “from the start” or “to the end”:
'abcde'[2:None] == 'abcde'[2:] == 'cde'
This is particularly helpful in functions, where you can’t provide an empty space as an argument:
def substring(s, start, end):
"""Remove `start` characters from the beginning and `end`
characters from the end of string `s`.
Examples
--------
>>> substring('abcde', 0, 3)
'abc'
>>> substring('abcde', 1, None)
'bcde'
"""
return s[start:end]
Python has slice objects:
idx = slice(2, None)
'abcde'[idx] == 'abcde'[2:] == 'cde'
回答 8
如果myString包含以偏移量6开始且长度为9的帐号,则可以通过以下方式提取该帐号: acct = myString[6:][:9]
。
如果OP接受,他们可能想尝试一下,
myString[2:][:999999]
它可以正常工作-不会引发任何错误,也不会发生默认的“字符串填充”。
If myString contains an account number that begins at offset 6 and has length 9, then you can extract the account number this way: acct = myString[6:][:9]
.
If the OP accepts that, they might want to try, in an experimental fashion,
myString[2:][:999999]
It works – no error is raised, and no default ‘string padding’ occurs.
回答 9
也许我错过了,但是在此页面上找不到原始问题的完整答案,因为这里没有进一步讨论变量。所以我不得不继续寻找。
由于尚未允许我发表评论,因此让我在这里添加我的结论。我确定访问此页面时,我不是唯一对此感兴趣的人:
>>>myString = 'Hello World'
>>>end = 5
>>>myString[2:end]
'llo'
如果您离开第一部分,您会得到
>>>myString[:end]
'Hello'
如果在中间也留下了:,则会得到最简单的子字符串,它是第5个字符(计数从0开始,因此在这种情况下为空白):
>>>myString[end]
' '
Maybe I missed it, but I couldn’t find a complete answer on this page to the original question(s) because variables are not further discussed here. So I had to go on searching.
Since I’m not yet allowed to comment, let me add my conclusion here. I’m sure I was not the only one interested in it when accessing this page:
>>>myString = 'Hello World'
>>>end = 5
>>>myString[2:end]
'llo'
If you leave the first part, you get
>>>myString[:end]
'Hello'
And if you left the : in the middle as well you got the simplest substring, which would be the 5th character (count starting with 0, so it’s the blank in this case):
>>>myString[end]
' '
回答 10
好吧,我遇到了需要将PHP脚本转换为Python的情况,并且它有许多用法substr(string, beginning, LENGTH)
。
如果选择Python,string[beginning:end]
则必须计算大量的结束索引,因此更简单的方法是使用string[beginning:][:length]
,这为我省去了很多麻烦。
Well, I got a situation where I needed to translate a PHP script to Python, and it had many usages of substr(string, beginning, LENGTH)
.
If I chose Python’s string[beginning:end]
I’d have to calculate a lot of end indexes, so the easier way was to use string[beginning:][:length]
, it saved me a lot of trouble.
回答 11
使用硬编码的索引本身可能是一团糟。
为了避免这种情况,Python提供了一个内置对象slice()
。
string = "my company has 1000$ on profit, but I lost 500$ gambling."
如果我们想知道我剩下多少钱。
正常解决方案:
final = int(string[15:19]) - int(string[43:46])
print(final)
>>>500
使用切片:
EARNINGS = slice(15, 19)
LOSSES = slice(43, 46)
final = int(string[EARNINGS]) - int(string[LOSSES])
print(final)
>>>500
使用切片可以获得可读性。
Using hardcoded indexes itself can be a mess.
In order to avoid that, Python offers a built-in object slice()
.
string = "my company has 1000$ on profit, but I lost 500$ gambling."
If we want to know how many money I got left.
Normal solution:
final = int(string[15:19]) - int(string[43:46])
print(final)
>>>500
Using slices:
EARNINGS = slice(15, 19)
LOSSES = slice(43, 46)
final = int(string[EARNINGS]) - int(string[LOSSES])
print(final)
>>>500
Using slice you gain readability.