问题：如何找到最多2个数字？
如何找到最多2个数字？
value = -9999
run = problem.getscore()
我需要比较两个值，即value，run并找到最大值2。我需要一些python函数来操作它吗？
How to find the maximum of 2 numbers?
value = -9999
run = problem.getscore()
I need to compare the 2 values i.e value and run and find the maximum of 2. I need some python function to operate it?
回答 0
使用内置功能 max。
例：
max(2, 4)返回4。
只是为了傻笑，还有一个min……您是否需要它。：P
Use the builtin function max.
Example:
max(2, 4) returns 4.
Just for giggles, there’s a min as well…should you need it. :P
回答 1
回答 2
max(number_one, number_two)
max(number_one, number_two)
回答 3
您可以使用 max(value, run)
该函数max接受任意数量的参数，或（可选）一个可迭代的参数，并返回最大值。
You can use max(value, run)
The function max takes any number of arguments, or (alternatively) an iterable, and returns the maximum value.
回答 4
max(value,run)
should do it.
回答 5
只是为了好玩，晚会结束后，马狂奔了。
答案是：max()！
Just for the fun of it, after the party has finished and the horse bolted.
The answer is: max() !
回答 6
您还可以通过使用条件表达式获得相同的结果：
maxnum = run if run > value else value
比max输入更灵活，但输入时间更长。
You could also achieve the same result by using a Conditional Expression:
maxnum = run if run > value else value
a bit more flexible than max but admittedly longer to type.
回答 7
(num1>=num2)*num1+(num2>num1)*num2 将返回两个值中的最大值。
(num1>=num2)*num1+(num2>num1)*num2 will return the maximum of two values.
回答 8
我注意到，如果您有除法将其四舍五入为整数，则最好使用：
c=float(max(a1,...,an))/b
对不起，晚发！
I noticed that if you have divisions it rounds off to integer, it would be better to use:
c=float(max(a1,...,an))/b
Sorry for the late post!
回答 9
numberList=[16,19,42,43,74,66]
largest = numberList[0]
for num2 in numberList:
if num2 > largest:
largest=num2
print(largest)
在不使用Max语句的情况下从数字列表中给出最大的数字
numberList=[16,19,42,43,74,66]
largest = numberList[0]
for num2 in numberList:
if num2 > largest:
largest=num2
print(largest)
gives largest number out of the numberslist without using a Max statement
