根据最后出现的分隔符将字符串分成2个

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问题：根据最后出现的分隔符将字符串分成2个

我想知道在python中是否有任何内置函数根据最后一次出现的分隔符将字符串分为2部分。

例如：考虑字符串“ abc，d，e，f”，在分隔符“，”分割后，我希望输出为

“ abc，d，e”和“ f”。

我知道如何操作字符串以获取所需的输出，但是我想知道python中是否有内置函数。

I would like to know if there is any built in function in python to break the string in to 2 parts, based on the last occurrence of a separator.

for eg: consider the string “a b c,d,e,f” , after the split over separator “,”, i want the output as

“a b c,d,e” and “f”.

I know how to manipulate the string to get the desired output, but i want to know if there is any in built function in python.

使用rpartition(s)。它确实做到了。

您也可以使用rsplit(s, 1)。

Use rpartition(s). It does exactly that.

You can also use rsplit(s, 1).

>>> "a b c,d,e,f".rsplit(',',1)
['a b c,d,e', 'f']

>>> "a b c,d,e,f".rsplit(',',1)
['a b c,d,e', 'f']

您可以使用最后一个分隔符来分割字符串rsplit：

返回字符串中的单词列表，以分隔符字符串分隔（从右开始）。

要以最后一个逗号分隔：

>>> "a b c,d,e,f".rsplit(',', 1)
['a b c,d,e', 'f']

You can split a string by the last occurrence of a separator with rsplit:

Returns a list of the words in the string, separated by the delimiter string (starting from right).

To split by the last comma:

>>> "a b c,d,e,f".rsplit(',', 1)
['a b c,d,e', 'f']