问题:正则表达式匹配多行文本块
与跨多行的文本进行匹配时,让Python正则表达式无法正常工作有点麻烦。示例文本为(“ \ n”是换行符)
some Varying TEXT\n
\n
DSJFKDAFJKDAFJDSAKFJADSFLKDLAFKDSAF\n
[more of the above, ending with a newline]\n
[yep, there is a variable number of lines here]\n
\n
(repeat the above a few hundred times).
我想捕获两件事:“ some_Varying_TEXT”部分,以及一次捕获中位于其下方两行的所有大写文本行(我以后可以去除换行符)。我尝试了几种方法:
re.compile(r"^>(\w+)$$([.$]+)^$", re.MULTILINE) # try to capture both parts
re.compile(r"(^[^>][\w\s]+)$", re.MULTILINE|re.DOTALL) # just textlines
并有很多变化,没有运气。最后一个似乎与文本行一一对应,这不是我真正想要的。我可以抓住第一部分,没问题,但是我似乎无法抓住4-5行的大写文本。我希望match.group(1)是some_Varying_Text,而group(2)是line1 + line2 + line3 + etc,直到遇到空行。
如果有人好奇,它应该是构成蛋白质的氨基酸序列。
I’m having a bit of trouble getting a Python regex to work when matching against text that spans multiple lines. The example text is (‘\n’ is a newline)
some Varying TEXT\n
\n
DSJFKDAFJKDAFJDSAKFJADSFLKDLAFKDSAF\n
[more of the above, ending with a newline]\n
[yep, there is a variable number of lines here]\n
\n
(repeat the above a few hundred times).
I’d like to capture two things: the ‘some_Varying_TEXT’ part, and all of the lines of uppercase text that comes two lines below it in one capture (i can strip out the newline characters later).
I’ve tried with a few approaches:
re.compile(r"^>(\w+)$$([.$]+)^$", re.MULTILINE) # try to capture both parts
re.compile(r"(^[^>][\w\s]+)$", re.MULTILINE|re.DOTALL) # just textlines
and a lot of variations hereof with no luck. The last one seems to match the lines of text one by one, which is not what I really want. I can catch the first part, no problem, but I can’t seem to catch the 4-5 lines of uppercase text.
I’d like match.group(1) to be some_Varying_Text and group(2) to be line1+line2+line3+etc until the empty line is encountered.
If anyone’s curious, its supposed to be a sequence of aminoacids that make up a protein.
回答 0
试试这个:
re.compile(r"^(.+)\n((?:\n.+)+)", re.MULTILINE)
我认为您的最大问题是,您期望^
和$
定位符匹配换行符,但它们不匹配。在多行模式,^
匹配立即位置以下换行符和$
立即位置相匹配前一个换行符。
同样要注意,换行符可以由换行符(\ n),回车符(\ r)或回车符+换行符(\ r \ n)组成。如果不确定目标文本仅使用换行符,则应使用此更广泛的正则表达式版本:
re.compile(r"^(.+)(?:\n|\r\n?)((?:(?:\n|\r\n?).+)+)", re.MULTILINE)
顺便说一句,您不想在这里使用DOTALL修饰符;您依赖点与换行符以外的所有内容都匹配的事实。
Try this:
re.compile(r"^(.+)\n((?:\n.+)+)", re.MULTILINE)
I think your biggest problem is that you’re expecting the ^
and $
anchors to match linefeeds, but they don’t. In multiline mode, ^
matches the position immediately following a newline and $
matches the position immediately preceding a newline.
Be aware, too, that a newline can consist of a linefeed (\n), a carriage-return (\r), or a carriage-return+linefeed (\r\n). If you aren’t certain that your target text uses only linefeeds, you should use this more inclusive version of the regex:
re.compile(r"^(.+)(?:\n|\r\n?)((?:(?:\n|\r\n?).+)+)", re.MULTILINE)
BTW, you don’t want to use the DOTALL modifier here; you’re relying on the fact that the dot matches everything except newlines.
回答 1
这将起作用:
>>> import re
>>> rx_sequence=re.compile(r"^(.+?)\n\n((?:[A-Z]+\n)+)",re.MULTILINE)
>>> rx_blanks=re.compile(r"\W+") # to remove blanks and newlines
>>> text="""Some varying text1
...
... AAABBBBBBCCCCCCDDDDDDD
... EEEEEEEFFFFFFFFGGGGGGG
... HHHHHHIIIIIJJJJJJJKKKK
...
... Some varying text 2
...
... LLLLLMMMMMMNNNNNNNOOOO
... PPPPPPPQQQQQQRRRRRRSSS
... TTTTTUUUUUVVVVVVWWWWWW
... """
>>> for match in rx_sequence.finditer(text):
... title, sequence = match.groups()
... title = title.strip()
... sequence = rx_blanks.sub("",sequence)
... print "Title:",title
... print "Sequence:",sequence
... print
...
Title: Some varying text1
Sequence: AAABBBBBBCCCCCCDDDDDDDEEEEEEEFFFFFFFFGGGGGGGHHHHHHIIIIIJJJJJJJKKKK
Title: Some varying text 2
Sequence: LLLLLMMMMMMNNNNNNNOOOOPPPPPPPQQQQQQRRRRRRSSSTTTTTUUUUUVVVVVVWWWWWW
关于此正则表达式的一些解释可能会有用: ^(.+?)\n\n((?:[A-Z]+\n)+)
- 第一个字符(
^
)表示“从行首开始”。请注意,它与换行符本身不匹配(与$相同:表示“仅在换行符之前”,但与换行符本身不匹配)。
- 然后
(.+?)\n\n
表示“匹配尽可能少的字符(允许所有字符),直到到达两个换行符”。结果(没有换行符)放在第一组中。
[A-Z]+\n
意思是“匹配尽可能多的大写字母,直到到达换行符为止。这定义了我称之为文本行。
((?:
文本行)+)
表示匹配一个或多个文本行,但不要将每一行都放在一组中。相反,把所有的文本行中的一组。
\n
如果要在末尾强制使用双换行符,则可以在正则表达式中添加final 。
- 另外,如果你不知道你会得到什么类型的换行符(
\n
或\r
或\r\n
),那么仅仅通过替换每次出现解决了正则表达式\n
的(?:\n|\r\n?)
。
This will work:
>>> import re
>>> rx_sequence=re.compile(r"^(.+?)\n\n((?:[A-Z]+\n)+)",re.MULTILINE)
>>> rx_blanks=re.compile(r"\W+") # to remove blanks and newlines
>>> text="""Some varying text1
...
... AAABBBBBBCCCCCCDDDDDDD
... EEEEEEEFFFFFFFFGGGGGGG
... HHHHHHIIIIIJJJJJJJKKKK
...
... Some varying text 2
...
... LLLLLMMMMMMNNNNNNNOOOO
... PPPPPPPQQQQQQRRRRRRSSS
... TTTTTUUUUUVVVVVVWWWWWW
... """
>>> for match in rx_sequence.finditer(text):
... title, sequence = match.groups()
... title = title.strip()
... sequence = rx_blanks.sub("",sequence)
... print "Title:",title
... print "Sequence:",sequence
... print
...
Title: Some varying text1
Sequence: AAABBBBBBCCCCCCDDDDDDDEEEEEEEFFFFFFFFGGGGGGGHHHHHHIIIIIJJJJJJJKKKK
Title: Some varying text 2
Sequence: LLLLLMMMMMMNNNNNNNOOOOPPPPPPPQQQQQQRRRRRRSSSTTTTTUUUUUVVVVVVWWWWWW
Some explanation about this regular expression might be useful: ^(.+?)\n\n((?:[A-Z]+\n)+)
- The first character (
^
) means “starting at the beginning of a line”. Be aware that it does not match the newline itself (same for $: it means “just before a newline”, but it does not match the newline itself).
- Then
(.+?)\n\n
means “match as few characters as possible (all characters are allowed) until you reach two newlines”. The result (without the newlines) is put in the first group.
[A-Z]+\n
means “match as many upper case letters as possible until you reach a newline. This defines what I will call a textline.
((?:
textline)+)
means match one or more textlines but do not put each line in a group. Instead, put all the textlines in one group.
- You could add a final
\n
in the regular expression if you want to enforce a double newline at the end.
- Also, if you are not sure about what type of newline you will get (
\n
or \r
or \r\n
) then just fix the regular expression by replacing every occurrence of \n
by (?:\n|\r\n?)
.
回答 2
如果每个文件只有一个氨基酸序列,我将完全不使用正则表达式。就像这样:
def read_amino_acid_sequence(path):
with open(path) as sequence_file:
title = sequence_file.readline() # read 1st line
aminoacid_sequence = sequence_file.read() # read the rest
# some cleanup, if necessary
title = title.strip() # remove trailing white spaces and newline
aminoacid_sequence = aminoacid_sequence.replace(" ","").replace("\n","")
return title, aminoacid_sequence
If each file only has one sequence of aminoacids, I wouldn’t use regular expressions at all. Just something like this:
def read_amino_acid_sequence(path):
with open(path) as sequence_file:
title = sequence_file.readline() # read 1st line
aminoacid_sequence = sequence_file.read() # read the rest
# some cleanup, if necessary
title = title.strip() # remove trailing white spaces and newline
aminoacid_sequence = aminoacid_sequence.replace(" ","").replace("\n","")
return title, aminoacid_sequence
回答 3
找:
^>([^\n\r]+)[\n\r]([A-Z\n\r]+)
\ 1 = some_varying_text
\ 2 =所有CAPS的行
编辑(证明这可行):
text = """> some_Varying_TEXT
DSJFKDAFJKDAFJDSAKFJADSFLKDLAFKDSAF
GATACAACATAGGATACA
GGGGGAAAAAAAATTTTTTTTT
CCCCAAAA
> some_Varying_TEXT2
DJASDFHKJFHKSDHF
HHASGDFTERYTERE
GAGAGAGAGAG
PPPPPAAAAAAAAAAAAAAAP
"""
import re
regex = re.compile(r'^>([^\n\r]+)[\n\r]([A-Z\n\r]+)', re.MULTILINE)
matches = [m.groups() for m in regex.finditer(text)]
for m in matches:
print 'Name: %s\nSequence:%s' % (m[0], m[1])
find:
^>([^\n\r]+)[\n\r]([A-Z\n\r]+)
\1 = some_varying_text
\2 = lines of all CAPS
Edit (proof that this works):
text = """> some_Varying_TEXT
DSJFKDAFJKDAFJDSAKFJADSFLKDLAFKDSAF
GATACAACATAGGATACA
GGGGGAAAAAAAATTTTTTTTT
CCCCAAAA
> some_Varying_TEXT2
DJASDFHKJFHKSDHF
HHASGDFTERYTERE
GAGAGAGAGAG
PPPPPAAAAAAAAAAAAAAAP
"""
import re
regex = re.compile(r'^>([^\n\r]+)[\n\r]([A-Z\n\r]+)', re.MULTILINE)
matches = [m.groups() for m in regex.finditer(text)]
for m in matches:
print 'Name: %s\nSequence:%s' % (m[0], m[1])
回答 4
以下是匹配多行文本块的正则表达式:
import re
result = re.findall('(startText)(.+)((?:\n.+)+)(endText)',input)
The following is a regular expression matching a multiline block of text:
import re
result = re.findall('(startText)(.+)((?:\n.+)+)(endText)',input)
回答 5
我的偏爱。
lineIter= iter(aFile)
for line in lineIter:
if line.startswith( ">" ):
someVaryingText= line
break
assert len( lineIter.next().strip() ) == 0
acids= []
for line in lineIter:
if len(line.strip()) == 0:
break
acids.append( line )
此时,您将someVaryingText作为字符串,并将酸作为字符串列表。您可以"".join( acids )
制作一个字符串。
我发现它比多行正则表达式更令人沮丧(并且更灵活)。
My preference.
lineIter= iter(aFile)
for line in lineIter:
if line.startswith( ">" ):
someVaryingText= line
break
assert len( lineIter.next().strip() ) == 0
acids= []
for line in lineIter:
if len(line.strip()) == 0:
break
acids.append( line )
At this point you have someVaryingText as a string, and the acids as a list of strings.
You can do "".join( acids )
to make a single string.
I find this less frustrating (and more flexible) than multiline regexes.