生成文件以使用Django下载

问题:生成文件以使用Django下载

是否可以制作一个zip归档文件并提供下载,但仍不将文件保存到硬盘驱动器?

Is it possible to make a zip archive and offer it to download, but still not save a file to the hard drive?


回答 0

要触发下载,您需要设置Content-Disposition标题:

from django.http import HttpResponse
from wsgiref.util import FileWrapper

# generate the file
response = HttpResponse(FileWrapper(myfile.getvalue()), content_type='application/zip')
response['Content-Disposition'] = 'attachment; filename=myfile.zip'
return response

如果您不想将文件放在磁盘上,则需要使用 StringIO

import cStringIO as StringIO

myfile = StringIO.StringIO()
while not_finished:
    # generate chunk
    myfile.write(chunk)

您也可以选择设置Content-Length标头:

response['Content-Length'] = myfile.tell()

To trigger a download you need to set Content-Disposition header:

from django.http import HttpResponse
from wsgiref.util import FileWrapper

# generate the file
response = HttpResponse(FileWrapper(myfile.getvalue()), content_type='application/zip')
response['Content-Disposition'] = 'attachment; filename=myfile.zip'
return response

If you don’t want the file on disk you need to use StringIO

import cStringIO as StringIO

myfile = StringIO.StringIO()
while not_finished:
    # generate chunk
    myfile.write(chunk)

Optionally you can set Content-Length header as well:

response['Content-Length'] = myfile.tell()

回答 1

您将更高兴创建一个临时文件。这样可以节省大量内存。当您同时拥有一个或两个以上用户时,您会发现节省内存非常重要。

但是,您可以写入StringIO对象。

>>> import zipfile
>>> import StringIO
>>> buffer= StringIO.StringIO()
>>> z= zipfile.ZipFile( buffer, "w" )
>>> z.write( "idletest" )
>>> z.close()
>>> len(buffer.getvalue())
778

“缓冲区”对象类似于具有778字节ZIP存档的文件。

You’ll be happier creating a temporary file. This saves a lot of memory. When you have more than one or two users concurrently, you’ll find the memory saving is very, very important.

You can, however, write to a StringIO object.

>>> import zipfile
>>> import StringIO
>>> buffer= StringIO.StringIO()
>>> z= zipfile.ZipFile( buffer, "w" )
>>> z.write( "idletest" )
>>> z.close()
>>> len(buffer.getvalue())
778

The “buffer” object is file-like with a 778 byte ZIP archive.


回答 2

为什么不制作tar文件呢?像这样:

def downloadLogs(req, dir):
    response = HttpResponse(content_type='application/x-gzip')
    response['Content-Disposition'] = 'attachment; filename=download.tar.gz'
    tarred = tarfile.open(fileobj=response, mode='w:gz')
    tarred.add(dir)
    tarred.close()

    return response

Why not make a tar file instead? Like so:

def downloadLogs(req, dir):
    response = HttpResponse(content_type='application/x-gzip')
    response['Content-Disposition'] = 'attachment; filename=download.tar.gz'
    tarred = tarfile.open(fileobj=response, mode='w:gz')
    tarred.add(dir)
    tarred.close()

    return response

回答 3

是的,您可以使用zipfile模块zlib模块或其他压缩模块在内存中创建一个zip存档。您可以使视图将zip归档文件写入HttpResponseDjango视图返回的对象,而不是将上下文发送到模板。最后,您需要将mimetype设置为适当的格式,以告知浏览器将响应视为file

Yes, you can use the zipfile module, zlib module or other compression modules to create a zip archive in memory. You can make your view write the zip archive to the HttpResponse object that the Django view returns instead of sending a context to a template. Lastly, you’ll need to set the mimetype to the appropriate format to tell the browser to treat the response as a file.


回答 4

models.py

from django.db import models

class PageHeader(models.Model):
    image = models.ImageField(upload_to='uploads')

views.py

from django.http import HttpResponse
from StringIO import StringIO
from models import *
import os, mimetypes, urllib

def random_header_image(request):
    header = PageHeader.objects.order_by('?')[0]
    image = StringIO(file(header.image.path, "rb").read())
    mimetype = mimetypes.guess_type(os.path.basename(header.image.name))[0]

    return HttpResponse(image.read(), mimetype=mimetype)

models.py

from django.db import models

class PageHeader(models.Model):
    image = models.ImageField(upload_to='uploads')

views.py

from django.http import HttpResponse
from StringIO import StringIO
from models import *
import os, mimetypes, urllib

def random_header_image(request):
    header = PageHeader.objects.order_by('?')[0]
    image = StringIO(file(header.image.path, "rb").read())
    mimetype = mimetypes.guess_type(os.path.basename(header.image.name))[0]

    return HttpResponse(image.read(), mimetype=mimetype)

回答 5


回答 6

def download_zip(request,file_name):
    filePath = '<path>/'+file_name
    fsock = open(file_name_with_path,"rb")
    response = HttpResponse(fsock, content_type='application/zip')
    response['Content-Disposition'] = 'attachment; filename=myfile.zip'
    return response

您可以根据需要替换zip和内容类型。

def download_zip(request,file_name):
    filePath = '<path>/'+file_name
    fsock = open(file_name_with_path,"rb")
    response = HttpResponse(fsock, content_type='application/zip')
    response['Content-Disposition'] = 'attachment; filename=myfile.zip'
    return response

You can replace zip and content type as per your requirement.


回答 7

与内存中的tgz存档相同:

import tarfile
from io import BytesIO


def serve_file(request):
    out = BytesIO()
    tar = tarfile.open(mode = "w:gz", fileobj = out)
    data = 'lala'.encode('utf-8')
    file = BytesIO(data)
    info = tarfile.TarInfo(name="1.txt")
    info.size = len(data)
    tar.addfile(tarinfo=info, fileobj=file)
    tar.close()

    response = HttpResponse(out.getvalue(), content_type='application/tgz')
    response['Content-Disposition'] = 'attachment; filename=myfile.tgz'
    return response

Same with in memory tgz archive:

import tarfile
from io import BytesIO


def serve_file(request):
    out = BytesIO()
    tar = tarfile.open(mode = "w:gz", fileobj = out)
    data = 'lala'.encode('utf-8')
    file = BytesIO(data)
    info = tarfile.TarInfo(name="1.txt")
    info.size = len(data)
    tar.addfile(tarinfo=info, fileobj=file)
    tar.close()

    response = HttpResponse(out.getvalue(), content_type='application/tgz')
    response['Content-Disposition'] = 'attachment; filename=myfile.tgz'
    return response