问题：Python日期字符串到日期对象
如何在python中将字符串转换为日期对象？
该字符串是："24052010"（对应于格式："%d%m%Y"）
我不想要datetime.datetime对象，而是想要datetime.date。
How do I convert a string to a date object in python?
The string would be: "24052010" (corresponding to the format: "%d%m%Y")
I don’t want a datetime.datetime object, but rather a datetime.date.
回答 0
您可以strptime在datetimePython包中使用：
>>> import datetime
>>> datetime.datetime.strptime('24052010', "%d%m%Y").date()
datetime.date(2010, 5, 24)
You can use strptime in the datetime package of Python:
>>> import datetime
>>> datetime.datetime.strptime('24052010', "%d%m%Y").date()
datetime.date(2010, 5, 24)
回答 1
import datetime
datetime.datetime.strptime('24052010', '%d%m%Y').date()
import datetime
datetime.datetime.strptime('24052010', '%d%m%Y').date()
回答 2
直接相关的问题：
如果有的话
datetime.datetime.strptime("2015-02-24T13:00:00-08:00", "%Y-%B-%dT%H:%M:%S-%H:%M").date()
你会得到：
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python2.7/_strptime.py", line 308, in _strptime
format_regex = _TimeRE_cache.compile(format)
File "/usr/local/lib/python2.7/_strptime.py", line 265, in compile
return re_compile(self.pattern(format), IGNORECASE)
File "/usr/local/lib/python2.7/re.py", line 194, in compile
return _compile(pattern, flags)
File "/usr/local/lib/python2.7/re.py", line 251, in _compile
raise error, v # invalid expression
sre_constants.error: redefinition of group name 'H' as group 7; was group 4
并且您尝试了：
<-24T13:00:00-08:00", "%Y-%B-%dT%HH:%MM:%SS-%HH:%MM").date()
但是您仍然可以得到上面的追溯。
回答：
>>> from dateutil.parser import parse
>>> from datetime import datetime
>>> parse("2015-02-24T13:00:00-08:00")
datetime.datetime(2015, 2, 24, 13, 0, tzinfo=tzoffset(None, -28800))
Directly related question:
What if you have
datetime.datetime.strptime("2015-02-24T13:00:00-08:00", "%Y-%B-%dT%H:%M:%S-%H:%M").date()
and you get:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python2.7/_strptime.py", line 308, in _strptime
format_regex = _TimeRE_cache.compile(format)
File "/usr/local/lib/python2.7/_strptime.py", line 265, in compile
return re_compile(self.pattern(format), IGNORECASE)
File "/usr/local/lib/python2.7/re.py", line 194, in compile
return _compile(pattern, flags)
File "/usr/local/lib/python2.7/re.py", line 251, in _compile
raise error, v # invalid expression
sre_constants.error: redefinition of group name 'H' as group 7; was group 4
and you tried:
<-24T13:00:00-08:00", "%Y-%B-%dT%HH:%MM:%SS-%HH:%MM").date()
but you still get the traceback above.
Answer:
>>> from dateutil.parser import parse
>>> from datetime import datetime
>>> parse("2015-02-24T13:00:00-08:00")
datetime.datetime(2015, 2, 24, 13, 0, tzinfo=tzoffset(None, -28800))
回答 3
如果您懒惰并且不想与字符串文字打架，则可以使用该parser模块。
from dateutil import parser
dt = parser.parse("Jun 1 2005 1:33PM")
print(dt.year, dt.month, dt.day,dt.hour, dt.minute, dt.second)
>2005 6 1 13 33 0
只是一点说明，我们在尝试匹配any字符串表示形式时，它的速度比10倍慢strptime
If you are lazy and don’t want to fight with string literals, you can just go with the parser module.
from dateutil import parser
dt = parser.parse("Jun 1 2005 1:33PM")
print(dt.year, dt.month, dt.day,dt.hour, dt.minute, dt.second)
>2005 6 1 13 33 0
Just a side note, as we are trying to match any string representation, it is 10x slower than strptime
回答 4
您有一个像这样的日期字符串“ 24052010”，并且您想要这个日期对象，
from datetime import datetime
cus_date = datetime.strptime("24052010", "%d%m%Y").date()
此cus_date将为您提供日期对象。
您可以使用此方法从日期对象中检索日期字符串，
cus_date.strftime("%d%m%Y")
you have a date string like this, “24052010” and you want date object for this,
from datetime import datetime
cus_date = datetime.strptime("24052010", "%d%m%Y").date()
this cus_date will give you date object.
you can retrieve date string from your date object using this,
cus_date.strftime("%d%m%Y")
回答 5
还有一个叫做arrowpython的很棒的库，可以对python日期进行操作。
import arrow
import datetime
a = arrow.get('24052010', 'DMYYYY').date()
print(isinstance(a, datetime.date)) # True
There is another library called arrow really great to make manipulation on python date.
import arrow
import datetime
a = arrow.get('24052010', 'DMYYYY').date()
print(isinstance(a, datetime.date)) # True
回答 6
使用时间模块转换数据。
程式码片段：
import time
tring='20150103040500'
var = int(time.mktime(time.strptime(tring, '%Y%m%d%H%M%S')))
print var
Use time module to convert data.
Code snippet:
import time
tring='20150103040500'
var = int(time.mktime(time.strptime(tring, '%Y%m%d%H%M%S')))
print var
