Python-ABS与工厂

问题:Python-ABS与工厂

我注意到在python中,有两种相似的寻找数字绝对值的方法:

第一

abs(-5)

第二

import math
math.fabs(-5)

这些方法有何不同?

I noticed that in python there are two similar looking methods for finding the absolute value of a number:

First

abs(-5)

Second

import math
math.fabs(-5)

How do these methods differ?


回答 0

math.fabs()如果可以,将其参数转换为float(如果不能,则抛出异常)。然后,它采用绝对值,并以浮点数形式返回结果。

除浮点数外,abs()还适用于整数和复数。其返回类型取决于其参数的类型。

In [7]: type(abs(-2))
Out[7]: int

In [8]: type(abs(-2.0))
Out[8]: float

In [9]: type(abs(3+4j))
Out[9]: float

In [10]: type(math.fabs(-2))
Out[10]: float

In [11]: type(math.fabs(-2.0))
Out[11]: float

In [12]: type(math.fabs(3+4j))
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
/home/npe/<ipython-input-12-8368761369da> in <module>()
----> 1 type(math.fabs(3+4j))

TypeError: can't convert complex to float

math.fabs() converts its argument to float if it can (if it can’t, it throws an exception). It then takes the absolute value, and returns the result as a float.

In addition to floats, abs() also works with integers and complex numbers. Its return type depends on the type of its argument.

In [7]: type(abs(-2))
Out[7]: int

In [8]: type(abs(-2.0))
Out[8]: float

In [9]: type(abs(3+4j))
Out[9]: float

In [10]: type(math.fabs(-2))
Out[10]: float

In [11]: type(math.fabs(-2.0))
Out[11]: float

In [12]: type(math.fabs(3+4j))
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
/home/npe/<ipython-input-12-8368761369da> in <module>()
----> 1 type(math.fabs(3+4j))

TypeError: can't convert complex to float

回答 1

编辑:正如@a​​ix所建议的,一种比较(更公平)速度差异的方法:

In [1]: %timeit abs(5)
10000000 loops, best of 3: 86.5 ns per loop

In [2]: from math import fabs

In [3]: %timeit fabs(5)
10000000 loops, best of 3: 115 ns per loop

In [4]: %timeit abs(-5)
10000000 loops, best of 3: 88.3 ns per loop

In [5]: %timeit fabs(-5)
10000000 loops, best of 3: 114 ns per loop

In [6]: %timeit abs(5.0)
10000000 loops, best of 3: 92.5 ns per loop

In [7]: %timeit fabs(5.0)
10000000 loops, best of 3: 93.2 ns per loop

In [8]: %timeit abs(-5.0)
10000000 loops, best of 3: 91.8 ns per loop

In [9]: %timeit fabs(-5.0)
10000000 loops, best of 3: 91 ns per loop

因此,它似乎abs()仅比fabs()整数具有轻微的速度优势。对于花车,abs()fabs()表现出类似的速度。


除了@aix所说的以外,还要考虑的另一件事是速度差异:

In [1]: %timeit abs(-5)
10000000 loops, best of 3: 102 ns per loop

In [2]: import math

In [3]: %timeit math.fabs(-5)
10000000 loops, best of 3: 194 ns per loop

因此abs()比快math.fabs()

Edit: as @aix suggested, a better (more fair) way to compare the speed difference:

In [1]: %timeit abs(5)
10000000 loops, best of 3: 86.5 ns per loop

In [2]: from math import fabs

In [3]: %timeit fabs(5)
10000000 loops, best of 3: 115 ns per loop

In [4]: %timeit abs(-5)
10000000 loops, best of 3: 88.3 ns per loop

In [5]: %timeit fabs(-5)
10000000 loops, best of 3: 114 ns per loop

In [6]: %timeit abs(5.0)
10000000 loops, best of 3: 92.5 ns per loop

In [7]: %timeit fabs(5.0)
10000000 loops, best of 3: 93.2 ns per loop

In [8]: %timeit abs(-5.0)
10000000 loops, best of 3: 91.8 ns per loop

In [9]: %timeit fabs(-5.0)
10000000 loops, best of 3: 91 ns per loop

So it seems abs() only has slight speed advantage over fabs() for integers. For floats, abs() and fabs() demonstrate similar speed.


In addition to what @aix has said, one more thing to consider is the speed difference:

In [1]: %timeit abs(-5)
10000000 loops, best of 3: 102 ns per loop

In [2]: import math

In [3]: %timeit math.fabs(-5)
10000000 loops, best of 3: 194 ns per loop

So abs() is faster than math.fabs().


回答 2

math.fabs()总是返回浮点数,而abs()可能返回整数。

math.fabs() always returns float, while abs() may return integer.


回答 3

abs():根据参数返回绝对值,即,如果参数为int则返回int,如果参数为float则返回float。它也适用于复杂变量,即abs(a+bj)也可以工作并返回绝对值,即math.sqrt(((a)**2)+((b)**2)

math.fabs():仅适用于整数或浮点值。无论参数类型是什么,总是返回绝对浮点值(复数除外)。

abs() : Returns the absolute value as per the argument i.e. if argument is int then it returns int, if argument is float it returns float. Also it works on complex variable also i.e. abs(a+bj) also works and returns absolute value i.e.math.sqrt(((a)**2)+((b)**2)

math.fabs() : It only works on the integer or float values. Always returns the absolute float value no matter what is the argument type(except for the complex numbers).