标签归档:do-while

在Python中模拟do-while循环?

问题:在Python中模拟do-while循环?

我需要在Python程序中模拟do-while循环。不幸的是,以下简单的代码不起作用:

list_of_ints = [ 1, 2, 3 ]
iterator = list_of_ints.__iter__()
element = None

while True:
  if element:
    print element

  try:
    element = iterator.next()
  except StopIteration:
    break

print "done"

代替“ 1,2,3,done”,它输出以下输出:

[stdout:]1
[stdout:]2
[stdout:]3
None['Traceback (most recent call last):
', '  File "test_python.py", line 8, in <module>
    s = i.next()
', 'StopIteration
']

为了捕获“停止迭代”异常并正确中断while循环,我该怎么办?

为什么需要这种东西的一个示例在下面显示为伪代码。

状态机:

s = ""
while True :
  if state is STATE_CODE :
    if "//" in s :
      tokens.add( TOKEN_COMMENT, s.split( "//" )[1] )
      state = STATE_COMMENT
    else :
      tokens.add( TOKEN_CODE, s )
  if state is STATE_COMMENT :
    if "//" in s :
      tokens.append( TOKEN_COMMENT, s.split( "//" )[1] )
    else
      state = STATE_CODE
      # Re-evaluate same line
      continue
  try :
    s = i.next()
  except StopIteration :
    break

I need to emulate a do-while loop in a Python program. Unfortunately, the following straightforward code does not work:

list_of_ints = [ 1, 2, 3 ]
iterator = list_of_ints.__iter__()
element = None

while True:
  if element:
    print element

  try:
    element = iterator.next()
  except StopIteration:
    break

print "done"

Instead of “1,2,3,done”, it prints the following output:

[stdout:]1
[stdout:]2
[stdout:]3
None['Traceback (most recent call last):
', '  File "test_python.py", line 8, in <module>
    s = i.next()
', 'StopIteration
']

What can I do in order to catch the ‘stop iteration’ exception and break a while loop properly?

An example of why such a thing may be needed is shown below as pseudocode.

State machine:

s = ""
while True :
  if state is STATE_CODE :
    if "//" in s :
      tokens.add( TOKEN_COMMENT, s.split( "//" )[1] )
      state = STATE_COMMENT
    else :
      tokens.add( TOKEN_CODE, s )
  if state is STATE_COMMENT :
    if "//" in s :
      tokens.append( TOKEN_COMMENT, s.split( "//" )[1] )
    else
      state = STATE_CODE
      # Re-evaluate same line
      continue
  try :
    s = i.next()
  except StopIteration :
    break

回答 0

我不确定您要做什么。您可以像这样实现一个do-while循环:

while True:
  stuff()
  if fail_condition:
    break

要么:

stuff()
while not fail_condition:
  stuff()

您在尝试使用do while循环来打印列表中的内容在做什么?为什么不使用:

for i in l:
  print i
print "done"

更新:

那你有行列表吗?而您想继续迭代呢?怎么样:

for s in l: 
  while True: 
    stuff() 
    # use a "break" instead of s = i.next()

看起来像您想要的东西吗?在您的代码示例中,它将是:

for s in some_list:
  while True:
    if state is STATE_CODE:
      if "//" in s:
        tokens.add( TOKEN_COMMENT, s.split( "//" )[1] )
        state = STATE_COMMENT
      else :
        tokens.add( TOKEN_CODE, s )
    if state is STATE_COMMENT:
      if "//" in s:
        tokens.append( TOKEN_COMMENT, s.split( "//" )[1] )
        break # get next s
      else:
        state = STATE_CODE
        # re-evaluate same line
        # continues automatically

I am not sure what you are trying to do. You can implement a do-while loop like this:

while True:
  stuff()
  if fail_condition:
    break

Or:

stuff()
while not fail_condition:
  stuff()

What are you doing trying to use a do while loop to print the stuff in the list? Why not just use:

for i in l:
  print i
print "done"

Update:

So do you have a list of lines? And you want to keep iterating through it? How about:

for s in l: 
  while True: 
    stuff() 
    # use a "break" instead of s = i.next()

Does that seem like something close to what you would want? With your code example, it would be:

for s in some_list:
  while True:
    if state is STATE_CODE:
      if "//" in s:
        tokens.add( TOKEN_COMMENT, s.split( "//" )[1] )
        state = STATE_COMMENT
      else :
        tokens.add( TOKEN_CODE, s )
    if state is STATE_COMMENT:
      if "//" in s:
        tokens.append( TOKEN_COMMENT, s.split( "//" )[1] )
        break # get next s
      else:
        state = STATE_CODE
        # re-evaluate same line
        # continues automatically

回答 1

这是一种模拟do-while循环的非常简单的方法:

condition = True
while condition:
    # loop body here
    condition = test_loop_condition()
# end of loop

同时执行循环的关键特征是循环主体始终至少执行一次,并且条件在循环主体的底部进行评估。此处显示的控制结构无需异常或break语句即可完成这两项操作。它确实引入了一个额外的布尔变量。

Here’s a very simple way to emulate a do-while loop:

condition = True
while condition:
    # loop body here
    condition = test_loop_condition()
# end of loop

The key features of a do-while loop are that the loop body always executes at least once, and that the condition is evaluated at the bottom of the loop body. The control structure show here accomplishes both of these with no need for exceptions or break statements. It does introduce one extra Boolean variable.


回答 2

我下面的代码可能是一个有用的实现,着重说明了两者之间的主要区别 据我了解。

因此,在这种情况下,您总是至少要循环一次。

first_pass = True
while first_pass or condition:
    first_pass = False
    do_stuff()

My code below might be a useful implementation, highlighting the main difference between vs as I understand it.

So in this one case, you always go through the loop at least once.

first_pass = True
while first_pass or condition:
    first_pass = False
    do_stuff()

回答 3

异常会破坏循环,因此您最好在循环之外进行处理。

try:
  while True:
    if s:
      print s
    s = i.next()
except StopIteration:   
  pass

我想您的代码的问题是break内部行为except未定义。通常break,仅上移一个级别,因此,例如breaktryInside直接进入finally(如果存在的话)a try,而不是循环。

相关的PEP:http
: //www.python.org/dev/peps/pep-3136相关的问题:打破嵌套循环

Exception will break the loop, so you might as well handle it outside the loop.

try:
  while True:
    if s:
      print s
    s = i.next()
except StopIteration:   
  pass

I guess that the problem with your code is that behaviour of break inside except is not defined. Generally break goes only one level up, so e.g. break inside try goes directly to finally (if it exists) an out of the try, but not out of the loop.

Related PEP: http://www.python.org/dev/peps/pep-3136
Related question: Breaking out of nested loops


回答 4

do {
  stuff()
} while (condition())

->

while True:
  stuff()
  if not condition():
    break

您可以执行以下功能:

def do_while(stuff, condition):
  while condition(stuff()):
    pass

但是1)这很丑。2)条件应该是带有一个参数的函数,应该由填充物填充(这是使用经典while循环的唯一原因。)

do {
  stuff()
} while (condition())

->

while True:
  stuff()
  if not condition():
    break

You can do a function:

def do_while(stuff, condition):
  while condition(stuff()):
    pass

But 1) It’s ugly. 2) Condition should be a function with one parameter, supposed to be filled by stuff (it’s the only reason not to use the classic while loop.)


回答 5

这是使用协程的不同模式的更疯狂的解决方案。代码仍然非常相似,但有一个重要区别。根本没有退出条件!当您停止向数据提供数据时,协程(实际上是协程链)就会停止。

def coroutine(func):
    """Coroutine decorator

    Coroutines must be started, advanced to their first "yield" point,
    and this decorator does this automatically.
    """
    def startcr(*ar, **kw):
        cr = func(*ar, **kw)
        cr.next()
        return cr
    return startcr

@coroutine
def collector(storage):
    """Act as "sink" and collect all sent in @storage"""
    while True:
        storage.append((yield))

@coroutine      
def state_machine(sink):
    """ .send() new parts to be tokenized by the state machine,
    tokens are passed on to @sink
    """ 
    s = ""
    state = STATE_CODE
    while True: 
        if state is STATE_CODE :
            if "//" in s :
                sink.send((TOKEN_COMMENT, s.split( "//" )[1] ))
                state = STATE_COMMENT
            else :
                sink.send(( TOKEN_CODE, s ))
        if state is STATE_COMMENT :
            if "//" in s :
                sink.send(( TOKEN_COMMENT, s.split( "//" )[1] ))
            else
                state = STATE_CODE
                # re-evaluate same line
                continue
        s = (yield)

tokens = []
sm = state_machine(collector(tokens))
for piece in i:
    sm.send(piece)

上述收集的代码中的所有令牌作为元组tokens和我假定之间不存在差异.append()并且.add()在原始代码中。

Here is a crazier solution of a different pattern — using coroutines. The code is still very similar, but with one important difference; there are no exit conditions at all! The coroutine (chain of coroutines really) just stops when you stop feeding it with data.

def coroutine(func):
    """Coroutine decorator

    Coroutines must be started, advanced to their first "yield" point,
    and this decorator does this automatically.
    """
    def startcr(*ar, **kw):
        cr = func(*ar, **kw)
        cr.next()
        return cr
    return startcr

@coroutine
def collector(storage):
    """Act as "sink" and collect all sent in @storage"""
    while True:
        storage.append((yield))

@coroutine      
def state_machine(sink):
    """ .send() new parts to be tokenized by the state machine,
    tokens are passed on to @sink
    """ 
    s = ""
    state = STATE_CODE
    while True: 
        if state is STATE_CODE :
            if "//" in s :
                sink.send((TOKEN_COMMENT, s.split( "//" )[1] ))
                state = STATE_COMMENT
            else :
                sink.send(( TOKEN_CODE, s ))
        if state is STATE_COMMENT :
            if "//" in s :
                sink.send(( TOKEN_COMMENT, s.split( "//" )[1] ))
            else
                state = STATE_CODE
                # re-evaluate same line
                continue
        s = (yield)

tokens = []
sm = state_machine(collector(tokens))
for piece in i:
    sm.send(piece)

The code above collects all tokens as tuples in tokens and I assume there is no difference between .append() and .add() in the original code.


回答 6

我这样做的方式如下…

condition = True
while condition:
     do_stuff()
     condition = (<something that evaluates to True or False>)

在我看来,这是一个简单的解决方案,我很惊讶自己还没有在这里看到它。显然,这也可以转化为

while not condition:

等等

The way I’ve done this is as follows…

condition = True
while condition:
     do_stuff()
     condition = (<something that evaluates to True or False>)

This seems to me to be the simplistic solution, I’m surprised I haven’t seen it here already. This can obviously also be inverted to

while not condition:

etc.


回答 7

做-包含try语句的while循环

loop = True
while loop:
    generic_stuff()
    try:
        questionable_stuff()
#       to break from successful completion
#       loop = False  
    except:
        optional_stuff()
#       to break from unsuccessful completion - 
#       the case referenced in the OP's question
        loop = False
   finally:
        more_generic_stuff()

或者,当不需要“ finally”子句时

while True:
    generic_stuff()
    try:
        questionable_stuff()
#       to break from successful completion
#       break  
    except:
        optional_stuff()
#       to break from unsuccessful completion - 
#       the case referenced in the OP's question
        break

for a do – while loop containing try statements

loop = True
while loop:
    generic_stuff()
    try:
        questionable_stuff()
#       to break from successful completion
#       loop = False  
    except:
        optional_stuff()
#       to break from unsuccessful completion - 
#       the case referenced in the OP's question
        loop = False
   finally:
        more_generic_stuff()

alternatively, when there’s no need for the ‘finally’ clause

while True:
    generic_stuff()
    try:
        questionable_stuff()
#       to break from successful completion
#       break  
    except:
        optional_stuff()
#       to break from unsuccessful completion - 
#       the case referenced in the OP's question
        break

回答 8

while condition is True: 
  stuff()
else:
  stuff()
while condition is True: 
  stuff()
else:
  stuff()

回答 9

快速破解:

def dowhile(func = None, condition = None):
    if not func or not condition:
        return
    else:
        func()
        while condition():
            func()

像这样使用:

>>> x = 10
>>> def f():
...     global x
...     x = x - 1
>>> def c():
        global x
        return x > 0
>>> dowhile(f, c)
>>> print x
0

Quick hack:

def dowhile(func = None, condition = None):
    if not func or not condition:
        return
    else:
        func()
        while condition():
            func()

Use like so:

>>> x = 10
>>> def f():
...     global x
...     x = x - 1
>>> def c():
        global x
        return x > 0
>>> dowhile(f, c)
>>> print x
0

回答 10

你为什么不做

for s in l :
    print s
print "done"

Why don’t you just do

for s in l :
    print s
print "done"

?


回答 11

看看是否有帮助:

在s之前,在异常处理程序中设置一个标志并检查它。

flagBreak = false;
while True :

    if flagBreak : break

    if s :
        print s
    try :
        s = i.next()
    except StopIteration :
        flagBreak = true

print "done"

See if this helps :

Set a flag inside the exception handler and check it before working on the s.

flagBreak = false;
while True :

    if flagBreak : break

    if s :
        print s
    try :
        s = i.next()
    except StopIteration :
        flagBreak = true

print "done"

回答 12

如果您处于资源不可用或可能引发异常的类似情况的循环环境中,则可以使用类似

import time

while True:
    try:
       f = open('some/path', 'r')
    except IOError:
       print('File could not be read. Retrying in 5 seconds')   
       time.sleep(5)
    else:
       break

If you’re in a scenario where you are looping while a resource is unavaliable or something similar that throws an exception, you could use something like

import time

while True:
    try:
       f = open('some/path', 'r')
    except IOError:
       print('File could not be read. Retrying in 5 seconds')   
       time.sleep(5)
    else:
       break

回答 13

对我来说,典型的while循环将是这样的:

xBool = True
# A counter to force a condition (eg. yCount = some integer value)

while xBool:
    # set up the condition (eg. if yCount > 0):
        (Do something)
        yCount = yCount - 1
    else:
        # (condition is not met, set xBool False)
        xBool = False

如果情况允许,我也可以在while循环中包含for..loop,以循环另一组条件。

For me a typical while loop will be something like this:

xBool = True
# A counter to force a condition (eg. yCount = some integer value)

while xBool:
    # set up the condition (eg. if yCount > 0):
        (Do something)
        yCount = yCount - 1
    else:
        # (condition is not met, set xBool False)
        xBool = False

I could include a for..loop within the while loop as well, if situation so warrants, for looping through another set of condition.