问题:使用Python sqlite3 API的表,数据库模式,转储等的列表
由于某种原因,我找不到一种方法来获取与sqlite的交互式shell命令等效的方法:
.tables
.dump
使用Python sqlite3 API。
有没有类似的东西?
回答 0
您可以通过查询SQLITE_MASTER表来获取表和模式列表:
sqlite> .tab
job snmptarget t1 t2 t3
sqlite> select name from sqlite_master where type = 'table';
job
t1
t2
snmptarget
t3
sqlite> .schema job
CREATE TABLE job (
id INTEGER PRIMARY KEY,
data VARCHAR
);
sqlite> select sql from sqlite_master where type = 'table' and name = 'job';
CREATE TABLE job (
id INTEGER PRIMARY KEY,
data VARCHAR
)
回答 1
在Python中:
con = sqlite3.connect('database.db')
cursor = con.cursor()
cursor.execute("SELECT name FROM sqlite_master WHERE type='table';")
print(cursor.fetchall())
当心我的其他答案。使用熊猫有更快的方法。
回答 2
在python中执行此操作的最快方法是使用Pandas(版本0.16及更高版本)。
转储一张桌子:
db = sqlite3.connect('database.db')
table = pd.read_sql_query("SELECT * from table_name", db)
table.to_csv(table_name + '.csv', index_label='index')
转储所有表:
import sqlite3
import pandas as pd
def to_csv():
db = sqlite3.connect('database.db')
cursor = db.cursor()
cursor.execute("SELECT name FROM sqlite_master WHERE type='table';")
tables = cursor.fetchall()
for table_name in tables:
table_name = table_name[0]
table = pd.read_sql_query("SELECT * from %s" % table_name, db)
table.to_csv(table_name + '.csv', index_label='index')
cursor.close()
db.close()
回答 3
我不熟悉Python API,但您可以随时使用
SELECT * FROM sqlite_master;
回答 4
这是一个简短的python程序,用于打印出这些表的表名和列名(后接python2。python 3)。
import sqlite3
db_filename = 'database.sqlite'
newline_indent = '\n '
db=sqlite3.connect(db_filename)
db.text_factory = str
cur = db.cursor()
result = cur.execute("SELECT name FROM sqlite_master WHERE type='table';").fetchall()
table_names = sorted(zip(*result)[0])
print "\ntables are:"+newline_indent+newline_indent.join(table_names)
for table_name in table_names:
result = cur.execute("PRAGMA table_info('%s')" % table_name).fetchall()
column_names = zip(*result)[1]
print ("\ncolumn names for %s:" % table_name)+newline_indent+(newline_indent.join(column_names))
db.close()
print "\nexiting."
(编辑:我一直在对此进行定期投票,所以这是针对找到此答案的人的python3版本)
import sqlite3
db_filename = 'database.sqlite'
newline_indent = '\n '
db=sqlite3.connect(db_filename)
db.text_factory = str
cur = db.cursor()
result = cur.execute("SELECT name FROM sqlite_master WHERE type='table';").fetchall()
table_names = sorted(list(zip(*result))[0])
print ("\ntables are:"+newline_indent+newline_indent.join(table_names))
for table_name in table_names:
result = cur.execute("PRAGMA table_info('%s')" % table_name).fetchall()
column_names = list(zip(*result))[1]
print (("\ncolumn names for %s:" % table_name)
+newline_indent
+(newline_indent.join(column_names)))
db.close()
print ("\nexiting.")
回答 5
显然,Python 2.6中包含的sqlite3版本具有此功能:http : //docs.python.org/dev/library/sqlite3.html
# Convert file existing_db.db to SQL dump file dump.sql
import sqlite3, os
con = sqlite3.connect('existing_db.db')
with open('dump.sql', 'w') as f:
for line in con.iterdump():
f.write('%s\n' % line)
回答 6
经过很多摆弄之后,我在sqlite文档中找到了一个更好的答案,它列出了表的元数据,甚至是附加的数据库。
meta = cursor.execute("PRAGMA table_info('Job')")
for r in meta:
print r
关键信息是前缀table_info,而不是带有附件句柄名称的my_table。
回答 7
如果有人想对熊猫做同样的事情
import pandas as pd
import sqlite3
conn = sqlite3.connect("db.sqlite3")
table = pd.read_sql_query("SELECT name FROM sqlite_master WHERE type='table'", conn)
print(table)
回答 8
在这里查看转储。似乎在sqlite3库中有一个转储函数。
回答 9
#!/usr/bin/env python
# -*- coding: utf-8 -*-
if __name__ == "__main__":
import sqlite3
dbname = './db/database.db'
try:
print "INITILIZATION..."
con = sqlite3.connect(dbname)
cursor = con.cursor()
cursor.execute("SELECT name FROM sqlite_master WHERE type='table';")
tables = cursor.fetchall()
for tbl in tables:
print "\n######## "+tbl[0]+" ########"
cursor.execute("SELECT * FROM "+tbl[0]+";")
rows = cursor.fetchall()
for row in rows:
print row
print(cursor.fetchall())
except KeyboardInterrupt:
print "\nClean Exit By user"
finally:
print "\nFinally"
回答 10
我已经在PHP中实现了sqlite表架构解析器,您可以在此处检查:https : //github.com/c9s/LazyRecord/blob/master/src/LazyRecord/TableParser/SqliteTableDefinitionParser.php
您可以使用此定义解析器来解析如下代码所示的定义:
$parser = new SqliteTableDefinitionParser;
$parser->parseColumnDefinitions('x INTEGER PRIMARY KEY, y DOUBLE, z DATETIME default \'2011-11-10\', name VARCHAR(100)');