问题：将两个LISTS的值之和添加到新的LIST中
我有以下两个列表：
first = [1,2,3,4,5]
second = [6,7,8,9,10]
现在，我想将这两个列表中的项目添加到新列表中。
输出应该是
third = [7,9,11,13,15]
I have the following two lists:
first = [1,2,3,4,5]
second = [6,7,8,9,10]
Now I want to add the items from both of these lists into a new list.
output should be
third = [7,9,11,13,15]
回答 0
此zip功能在此处有用，可与列表推导一起使用。
[x + y for x, y in zip(first, second)]
如果您有一个列表列表（而不是两个列表）：
lists_of_lists = [[1, 2, 3], [4, 5, 6]]
[sum(x) for x in zip(*lists_of_lists)]
# -> [5, 7, 9]
The zip function is useful here, used with a list comprehension.
[x + y for x, y in zip(first, second)]
If you have a list of lists (instead of just two lists):
lists_of_lists = [[1, 2, 3], [4, 5, 6]]
[sum(x) for x in zip(*lists_of_lists)]
# -> [5, 7, 9]
回答 1
来自文档
import operator
list(map(operator.add, first,second))
From docs
import operator
list(map(operator.add, first,second))
回答 2
假设两个列表a，并b具有相同的长度，你不需要压缩，numpy的或其他任何东西。
Python 2.x和3.x：
[a[i]+b[i] for i in range(len(a))]
Assuming both lists a and b have same length, you do not need zip, numpy or anything else.
Python 2.x and 3.x:
[a[i]+b[i] for i in range(len(a))]
回答 3
numpy中的默认行为是逐组件添加
import numpy as np
np.add(first, second)
哪个输出
array([7,9,11,13,15])
Default behavior in numpy is add componentwise
import numpy as np
np.add(first, second)
which outputs
array([7,9,11,13,15])
回答 4
这可以扩展到任意数量的列表：
[sum(sublist) for sublist in itertools.izip(*myListOfLists)]
在你的情况下，myListOfLists将[first, second]
This extends itself to any number of lists:
[sum(sublist) for sublist in itertools.izip(*myListOfLists)]
In your case, myListOfLists would be [first, second]
回答 5
尝试以下代码：
first = [1, 2, 3, 4]
second = [2, 3, 4, 5]
third = map(sum, zip(first, second))
Try the following code:
first = [1, 2, 3, 4]
second = [2, 3, 4, 5]
third = map(sum, zip(first, second))
回答 6
执行此操作的简单方法和快速方法是：
three = [sum(i) for i in zip(first,second)] # [7,9,11,13,15]
另外，您可以使用numpy sum：
from numpy import sum
three = sum([first,second], axis=0) # array([7,9,11,13,15])
The easy way and fast way to do this is:
three = [sum(i) for i in zip(first,second)] # [7,9,11,13,15]
Alternatively, you can use numpy sum:
from numpy import sum
three = sum([first,second], axis=0) # array([7,9,11,13,15])
回答 7
first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
three = map(lambda x,y: x+y,first,second)
print three
Output
[7, 9, 11, 13, 15]
first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
three = map(lambda x,y: x+y,first,second)
print three
Output
[7, 9, 11, 13, 15]
回答 8
一线解决方案
list(map(lambda x,y: x+y, a,b))
one-liner solution
list(map(lambda x,y: x+y, a,b))
回答 9
Thiru在3月17日9:25回答了我的问题。
这更加简单快捷，这是他的解决方案：
执行此操作的简单方法和快速方法是：
three = [sum(i) for i in zip(first,second)] # [7,9,11,13,15]
另外，您可以使用numpy sum：
from numpy import sum
three = sum([first,second], axis=0) # array([7,9,11,13,15])
您需要numpy！
numpy数组可以做一些像矢量的操作
import numpy as np
a = [1,2,3,4,5]
b = [6,7,8,9,10]
c = list(np.array(a) + np.array(b))
print c
# [7, 9, 11, 13, 15]
My answer is repeated with Thiru’s that answered it in Mar 17 at 9:25.
It was simpler and quicker, here are his solutions:
The easy way and fast way to do this is:
three = [sum(i) for i in zip(first,second)] # [7,9,11,13,15]
Alternatively, you can use numpy sum:
from numpy import sum
three = sum([first,second], axis=0) # array([7,9,11,13,15])
You need numpy!
numpy array could do some operation like vectors
import numpy as np
a = [1,2,3,4,5]
b = [6,7,8,9,10]
c = list(np.array(a) + np.array(b))
print c
# [7, 9, 11, 13, 15]
回答 10
如果未知数量的相同长度的列表，则可以使用以下功能。
在这里，* args接受可变数量的列表参数（但每个参数仅求和相同数量的元素）。再次使用*来解压缩每个列表中的元素。
def sum_lists(*args):
return list(map(sum, zip(*args)))
a = [1,2,3]
b = [1,2,3]
sum_lists(a,b)
输出：
[2, 4, 6]
或有3个清单
sum_lists([5,5,5,5,5], [10,10,10,10,10], [4,4,4,4,4])
输出：
[19, 19, 19, 19, 19]
If you have an unknown number of lists of the same length, you can use the below function.
Here the *args accepts a variable number of list arguments (but only sums the same number of elements in each).
The * is used again to unpack the elements in each of the lists.
def sum_lists(*args):
return list(map(sum, zip(*args)))
a = [1,2,3]
b = [1,2,3]
sum_lists(a,b)
Output:
[2, 4, 6]
Or with 3 lists
sum_lists([5,5,5,5,5], [10,10,10,10,10], [4,4,4,4,4])
Output:
[19, 19, 19, 19, 19]
回答 11
您可以使用zip()，将两个数组“交织”在一起，然后使用map()，它将对一个可迭代对象中的每个元素应用一个函数：
>>> a = [1,2,3,4,5]
>>> b = [6,7,8,9,10]
>>> zip(a, b)
[(1, 6), (2, 7), (3, 8), (4, 9), (5, 10)]
>>> map(lambda x: x[0] + x[1], zip(a, b))
[7, 9, 11, 13, 15]
You can use zip(), which will “interleave” the two arrays together, and then map(), which will apply a function to each element in an iterable:
>>> a = [1,2,3,4,5]
>>> b = [6,7,8,9,10]
>>> zip(a, b)
[(1, 6), (2, 7), (3, 8), (4, 9), (5, 10)]
>>> map(lambda x: x[0] + x[1], zip(a, b))
[7, 9, 11, 13, 15]
回答 12
这是另一种方法。我们利用python的内部__add__函数：
class SumList(object):
def __init__(self, this_list):
self.mylist = this_list
def __add__(self, other):
new_list = []
zipped_list = zip(self.mylist, other.mylist)
for item in zipped_list:
new_list.append(item[0] + item[1])
return SumList(new_list)
def __repr__(self):
return str(self.mylist)
list1 = SumList([1,2,3,4,5])
list2 = SumList([10,20,30,40,50])
sum_list1_list2 = list1 + list2
print(sum_list1_list2)
输出量
[11, 22, 33, 44, 55]
Here is another way to do it. We make use of the internal __add__ function of python:
class SumList(object):
def __init__(self, this_list):
self.mylist = this_list
def __add__(self, other):
new_list = []
zipped_list = zip(self.mylist, other.mylist)
for item in zipped_list:
new_list.append(item[0] + item[1])
return SumList(new_list)
def __repr__(self):
return str(self.mylist)
list1 = SumList([1,2,3,4,5])
list2 = SumList([10,20,30,40,50])
sum_list1_list2 = list1 + list2
print(sum_list1_list2)
Output
[11, 22, 33, 44, 55]
回答 13
如果您还想添加列表中的其余值，则可以使用它（在Python3.5中有效）
def addVectors(v1, v2):
sum = [x + y for x, y in zip(v1, v2)]
if not len(v1) >= len(v2):
sum += v2[len(v1):]
else:
sum += v1[len(v2):]
return sum
#for testing
if __name__=='__main__':
a = [1, 2]
b = [1, 2, 3, 4]
print(a)
print(b)
print(addVectors(a,b))
If you want to add also the rest of the values in the lists you can use this (this is working in Python3.5)
def addVectors(v1, v2):
sum = [x + y for x, y in zip(v1, v2)]
if not len(v1) >= len(v2):
sum += v2[len(v1):]
else:
sum += v1[len(v2):]
return sum
#for testing
if __name__=='__main__':
a = [1, 2]
b = [1, 2, 3, 4]
print(a)
print(b)
print(addVectors(a,b))
回答 14
first = [1,2,3,4,5]
second = [6,7,8,9,10]
#one way
third = [x + y for x, y in zip(first, second)]
print("third" , third)
#otherway
fourth = []
for i,j in zip(first,second):
global fourth
fourth.append(i + j)
print("fourth" , fourth )
#third [7, 9, 11, 13, 15]
#fourth [7, 9, 11, 13, 15]
first = [1,2,3,4,5]
second = [6,7,8,9,10]
#one way
third = [x + y for x, y in zip(first, second)]
print("third" , third)
#otherway
fourth = []
for i,j in zip(first,second):
global fourth
fourth.append(i + j)
print("fourth" , fourth )
#third [7, 9, 11, 13, 15]
#fourth [7, 9, 11, 13, 15]
回答 15
这是另一种方法。它对我来说很好。
N=int(input())
num1 = list(map(int, input().split()))
num2 = list(map(int, input().split()))
sum=[]
for i in range(0,N):
sum.append(num1[i]+num2[i])
for element in sum:
print(element, end=" ")
print("")
Here is another way to do it.It is working fine for me .
N=int(input())
num1 = list(map(int, input().split()))
num2 = list(map(int, input().split()))
sum=[]
for i in range(0,N):
sum.append(num1[i]+num2[i])
for element in sum:
print(element, end=" ")
print("")
回答 16
j = min(len(l1), len(l2))
l3 = [l1[i]+l2[i] for i in range(j)]
j = min(len(l1), len(l2))
l3 = [l1[i]+l2[i] for i in range(j)]
回答 17
也许是最简单的方法：
first = [1,2,3,4,5]
second = [6,7,8,9,10]
three=[]
for i in range(0,5):
three.append(first[i]+second[i])
print(three)
Perhaps the simplest approach:
first = [1,2,3,4,5]
second = [6,7,8,9,10]
three=[]
for i in range(0,5):
three.append(first[i]+second[i])
print(three)
回答 18
如果您将列表视为numpy数组，则需要轻松对其求和：
import numpy as np
third = np.array(first) + np.array(second)
print third
[7, 9, 11, 13, 15]
If you consider your lists as numpy array, then you need to easily sum them:
import numpy as np
third = np.array(first) + np.array(second)
print third
[7, 9, 11, 13, 15]
回答 19
如果您有不同长度的列表怎么办，那么您可以尝试这样的操作（使用zip_longest）
from itertools import zip_longest # izip_longest for python2.x
l1 = [1, 2, 3]
l2 = [4, 5, 6, 7]
>>> list(map(sum, zip_longest(l1, l2, fillvalue=0)))
[5, 7, 9, 7]
What if you have list with different length,
then you can try something like this (using zip_longest)
from itertools import zip_longest # izip_longest for python2.x
l1 = [1, 2, 3]
l2 = [4, 5, 6, 7]
>>> list(map(sum, zip_longest(l1, l2, fillvalue=0)))
[5, 7, 9, 7]
回答 20
您可以使用此方法，但仅当两个列表的大小相同时，该方法才有效：
first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
third = []
a = len(first)
b = int(0)
while True:
x = first[b]
y = second[b]
ans = x + y
third.append(ans)
b = b + 1
if b == a:
break
print third
You can use this method but it will work only if both the list are of the same size:
first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
third = []
a = len(first)
b = int(0)
while True:
x = first[b]
y = second[b]
ans = x + y
third.append(ans)
b = b + 1
if b == a:
break
print third
