问题：如何创建等于15分钟前的DateTime？
我需要创建一个DateTime对象，该对象代表当前时间减去15分钟。
I need to create a DateTime object that represents the current time minus 15 minutes.
回答 0
导入datetime，然后导入神奇的timedelta内容：
In [63]: datetime.datetime.now()
Out[63]: datetime.datetime(2010, 12, 27, 14, 39, 19, 700401)
In [64]: datetime.datetime.now() - datetime.timedelta(minutes=15)
Out[64]: datetime.datetime(2010, 12, 27, 14, 24, 21, 684435)
import datetime and then the magic timedelta stuff:
In [63]: datetime.datetime.now()
Out[63]: datetime.datetime(2010, 12, 27, 14, 39, 19, 700401)
In [64]: datetime.datetime.now() - datetime.timedelta(minutes=15)
Out[64]: datetime.datetime(2010, 12, 27, 14, 24, 21, 684435)
回答 1
datetime.datetime.now() - datetime.timedelta(minutes=15)
datetime.datetime.now() - datetime.timedelta(minutes=15)
回答 2
这就是要做的事情：
datetime.datetime.now() - datetime.timedelta(minutes = 15)
timedeltas是专门设计用来允许您减去datetimes 或增加s （差）。
This is simply what to do:
datetime.datetime.now() - datetime.timedelta(minutes = 15)
timedeltas are specifically designed to allow you to subtract or add deltas (differences) to datetimes.
回答 3
from datetime import timedelta
datetime.datetime.now() - datetime.timedelta(0, 900)
Actually 900 is in seconds. Which is equal to 15 minutes. `15*60 = 900`
from datetime import timedelta
datetime.datetime.now() - datetime.timedelta(0, 900)
Actually 900 is in seconds. Which is equal to 15 minutes. `15*60 = 900`
回答 4
如果您想查看更多示例，那么在几分钟，几年和几小时内，我提供了两种方法：
import datetime
print(datetime.datetime.now())
print(datetime.datetime.now() - datetime.timedelta(minutes = 15))
print(datetime.datetime.now() + datetime.timedelta(minutes = -15))
print(datetime.timedelta(hours = 5))
print(datetime.datetime.now() + datetime.timedelta(days = 3))
print(datetime.datetime.now() + datetime.timedelta(days = -9))
print(datetime.datetime.now() - datetime.timedelta(days = 9))
我得到以下结果：
2016-06-03 16:04:03.706615
2016-06-03 15:49:03.706622
2016-06-03 15:49:03.706642
5:00:00
2016-06-06 16:04:03.706665
2016-05-25 16:04:03.706676
2016-05-25 16:04:03.706687
2016-06-03
16:04:03.706716
I have provide two methods for doing so for minutes as well as for years and hours if you want to see more examples:
import datetime
print(datetime.datetime.now())
print(datetime.datetime.now() - datetime.timedelta(minutes = 15))
print(datetime.datetime.now() + datetime.timedelta(minutes = -15))
print(datetime.timedelta(hours = 5))
print(datetime.datetime.now() + datetime.timedelta(days = 3))
print(datetime.datetime.now() + datetime.timedelta(days = -9))
print(datetime.datetime.now() - datetime.timedelta(days = 9))
I get the following results:
2016-06-03 16:04:03.706615
2016-06-03 15:49:03.706622
2016-06-03 15:49:03.706642
5:00:00
2016-06-06 16:04:03.706665
2016-05-25 16:04:03.706676
2016-05-25 16:04:03.706687
2016-06-03
16:04:03.706716
回答 5
回答 6
datetime.datetime.now() - datetime.timedelta(0, 15 * 60)
timedelta是“时间的变化”。以天为第一个参数，以秒为第二个参数。15 * 60秒是15分钟。
datetime.datetime.now() - datetime.timedelta(0, 15 * 60)
timedelta is a “change in time”. It takes days as the first parameter and seconds in the second parameter. 15 * 60 seconds is 15 minutes.
回答 7
如果您使用的是time.time()时间戳记作为输出
只需使用
CONSTANT_SECONDS = 900 # time in seconds (900 seconds = 15 min)
current_time = int(time.time())
time_before_15_min = current_time - CONSTANT_SECONDS
您可以根据所需时间更改900秒。
If you are using time.time() and wants timestamp as output
Simply use
CONSTANT_SECONDS = 900 # time in seconds (900 seconds = 15 min)
current_time = int(time.time())
time_before_15_min = current_time - CONSTANT_SECONDS
You can change 900 seconds as per your required time.
回答 8
只有以下Python 3.7中的代码对我有用
from datetime import datetime,timedelta
print(datetime.now()-timedelta(seconds=900))
only the below code in Python 3.7 worked for me
from datetime import datetime,timedelta
print(datetime.now()-timedelta(seconds=900))
