如何将python datetime转换为具有可读格式date的字符串?

问题:如何将python datetime转换为具有可读格式date的字符串?

t = e['updated_parsed']
dt = datetime.datetime(t[0],t[1],t[2],t[3],t[4],t[5],t[6]
print dt
>>>2010-01-28 08:39:49.000003

如何将其转换为字符串?:

"January 28, 2010"
t = e['updated_parsed']
dt = datetime.datetime(t[0],t[1],t[2],t[3],t[4],t[5],t[6]
print dt
>>>2010-01-28 08:39:49.000003

How do I turn that into a string?:

"January 28, 2010"

回答 0

datetime类具有strftime方法。Python文档记录了它接受的不同格式:

对于此特定示例,它将类似于:

my_datetime.strftime("%B %d, %Y")

The datetime class has a method strftime. The Python docs documents the different formats it accepts:

For this specific example, it would look something like:

my_datetime.strftime("%B %d, %Y")

回答 1

这是您可以使用python的常规格式化功能来完成的操作…

>>>from datetime import datetime
>>>"{:%B %d, %Y}".format(datetime.now())

此处使用的格式字符与strftime所使用的格式字符相同。不要错过: 格式说明符的开头。

在大多数情况下,使用format()代替strftime()可以使代码更具可读性,易于编写,并且与格式化输出的生成方式保持一致…

>>>"{} today's date is: {:%B %d, %Y}".format("Andre", datetime.now())

将以上内容与以下strftime()替代项进行比较…

>>>"{} today's date is {}".format("Andre", datetime.now().strftime("%B %d, %Y"))

此外,以下内容将无法工作…

>>>datetime.now().strftime("%s %B %d, %Y" % "Andre")
Traceback (most recent call last):
  File "<pyshell#11>", line 1, in <module>
    datetime.now().strftime("%s %B %d, %Y" % "Andre")
TypeError: not enough arguments for format string

等等…

Here is how you can accomplish the same using python’s general formatting function…

>>>from datetime import datetime
>>>"{:%B %d, %Y}".format(datetime.now())

The formatting characters used here are the same as those used by strftime. Don’t miss the leading : in the format specifier.

Using format() instead of strftime() in most cases can make the code more readable, easier to write and consistent with the way formatted output is generated…

>>>"{} today's date is: {:%B %d, %Y}".format("Andre", datetime.now())

Compare the above with the following strftime() alternative…

>>>"{} today's date is {}".format("Andre", datetime.now().strftime("%B %d, %Y"))

Moreover, the following is not going to work…

>>>datetime.now().strftime("%s %B %d, %Y" % "Andre")
Traceback (most recent call last):
  File "<pyshell#11>", line 1, in <module>
    datetime.now().strftime("%s %B %d, %Y" % "Andre")
TypeError: not enough arguments for format string

And so on…


回答 2

在Python 3.6及更高版本中使用f字符串。

from datetime import datetime

date_string = f'{datetime.now():%Y-%m-%d %H:%M:%S%z}'

Using f-strings, in Python 3.6+.

from datetime import datetime

date_string = f'{datetime.now():%Y-%m-%d %H:%M:%S%z}'

回答 3

我知道很老的问题。但是有了新的f字符串(从python 3.6开始),就有了新的选择。所以这里是为了完整性:

from datetime import datetime

dt = datetime.now()

# str.format
strg = '{:%B %d, %Y}'.format(dt)
print(strg)  # July 22, 2017

# datetime.strftime
strg = dt.strftime('%B %d, %Y')
print(strg)  # July 22, 2017

# f-strings in python >= 3.6
strg = f'{dt:%B %d, %Y}'
print(strg)  # July 22, 2017

strftime()and strptime()Behavior解释格式说明符的含义。

very old question, i know. but with the new f-strings (starting from python 3.6) there are fresh options. so here for completeness:

from datetime import datetime

dt = datetime.now()

# str.format
strg = '{:%B %d, %Y}'.format(dt)
print(strg)  # July 22, 2017

# datetime.strftime
strg = dt.strftime('%B %d, %Y')
print(strg)  # July 22, 2017

# f-strings in python >= 3.6
strg = f'{dt:%B %d, %Y}'
print(strg)  # July 22, 2017

strftime() and strptime() Behavior explains what the format specifiers mean.


回答 4

阅读官方文档中的strfrtime

Read strfrtime from the official docs.


回答 5

Python datetime对象具有method属性,该属性以可读格式打印。

>>> a = datetime.now()
>>> a.ctime()
'Mon May 21 18:35:18 2018'
>>> 

Python datetime object has a method attribute, which prints in readable format.

>>> a = datetime.now()
>>> a.ctime()
'Mon May 21 18:35:18 2018'
>>> 

回答 6

这是用于格式化的日期吗?

def format_date(day, month, year):
        # {} betekent 'plaats hier stringvoorstelling van volgend argument'
        return "{}/{}/{}".format(day, month, year)

This is for format the date?

def format_date(day, month, year):
        # {} betekent 'plaats hier stringvoorstelling van volgend argument'
        return "{}/{}/{}".format(day, month, year)