问题：Python日期时间到没有微秒组件的字符串
我正在将UTC时间字符串添加到当前仅包含Amsterdam（！）时间字符串的Bitbucket API响应中。为了与其他地方返回的UTC时间字符串保持一致，请使用所需的格式2011-11-03 11:07:04（后跟+00:00，但这不是紧密联系）。
什么是创建这样一个字符串（最好的方式，而不从一微秒组件）datetime的实例与微秒组成部分？
>>> import datetime
>>> print unicode(datetime.datetime.now())
2011-11-03 11:13:39.278026
我会添加出现在我身上的最佳选择作为可能的答案，但是可能会有更优雅的解决方案。
编辑：我应该提一下，我实际上并不是在打印当前时间-我曾经datetime.now提供一个简单的例子。因此，该解决方案不应假定datetime其接收到的任何实例都将包含微秒组件。
I’m adding UTC time strings to Bitbucket API responses that currently only contain Amsterdam (!) time strings. For consistency with the UTC time strings returned elsewhere, the desired format is 2011-11-03 11:07:04 (followed by +00:00, but that’s not germane).
What’s the best way to create such a string (without a microsecond component) from a datetime instance with a microsecond component?
>>> import datetime
>>> print unicode(datetime.datetime.now())
2011-11-03 11:13:39.278026
I’ll add the best option that’s occurred to me as a possible answer, but there may well be a more elegant solution.
Edit: I should mention that I’m not actually printing the current time – I used datetime.now to provide a quick example. So the solution should not assume that any datetime instances it receives will include microsecond components.
回答 0
如果要以datetime不同于标准格式的特定格式格式化对象，则最好明确指定该格式：
>>> datetime.datetime.now().strftime("%Y-%m-%d %H:%M:%S")
'2011-11-03 18:21:26'
有关指令的说明，请参见的文档datetime.strftime()%。
If you want to format a datetime object in a specific format that is different from the standard format, it’s best to explicitly specify that format:
>>> datetime.datetime.now().strftime("%Y-%m-%d %H:%M:%S")
'2011-11-03 18:21:26'
See the documentation of datetime.strftime() for an explanation of the % directives.
回答 1
>>> import datetime
>>> now = datetime.datetime.now()
>>> print unicode(now.replace(microsecond=0))
2011-11-03 11:19:07
>>> import datetime
>>> now = datetime.datetime.now()
>>> print unicode(now.replace(microsecond=0))
2011-11-03 11:19:07
回答 2
回答 3
这就是我做到的方式。ISO格式：
import datetime
datetime.datetime.now().replace(microsecond=0).isoformat()
# Returns: '2017-01-23T14:58:07'
如果您不想使用ISO格式，则可以替换为’T’：
datetime.datetime.now().replace(microsecond=0).isoformat(' ')
# Returns: '2017-01-23 15:05:27'
This is the way I do it. ISO format:
import datetime
datetime.datetime.now().replace(microsecond=0).isoformat()
# Returns: '2017-01-23T14:58:07'
You can replace the ‘T’ if you don’t want ISO format:
datetime.datetime.now().replace(microsecond=0).isoformat(' ')
# Returns: '2017-01-23 15:05:27'
回答 4
另一个选择：
>>> import time
>>> time.strftime("%Y-%m-%d %H:%M:%S")
'2011-11-03 11:31:28'
默认情况下，这使用本地时间，如果您需要UTC，则可以使用以下时间：
>>> time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime())
'2011-11-03 18:32:20'
Yet another option:
>>> import time
>>> time.strftime("%Y-%m-%d %H:%M:%S")
'2011-11-03 11:31:28'
By default this uses local time, if you need UTC you can use the following:
>>> time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime())
'2011-11-03 18:32:20'
回答 5
通过切片保留所需的前19个字符：
>>> str(datetime.datetime.now())[:19]
'2011-11-03 14:37:50'
Keep the first 19 characters that you wanted via slicing:
>>> str(datetime.datetime.now())[:19]
'2011-11-03 14:37:50'
回答 6
我通常这样做：
import datetime
now = datetime.datetime.now()
now = now.replace(microsecond=0) # To print now without microsecond.
# To print now:
print(now)
输出：
2019-01-13 14:40:28
I usually do:
import datetime
now = datetime.datetime.now()
now = now.replace(microsecond=0) # To print now without microsecond.
# To print now:
print(now)
output:
2019-01-13 14:40:28
回答 7
由于并非所有datetime.datetime实例都具有微秒成分（即当它为零时），因此可以将字符串划分为“”。并只取第一项，它将始终有效：
unicode(datetime.datetime.now()).partition('.')[0]
Since not all datetime.datetime instances have a microsecond component (i.e. when it is zero), you can partition the string on a “.” and take only the first item, which will always work:
unicode(datetime.datetime.now()).partition('.')[0]
回答 8
我们可以尝试如下
import datetime
date_generated = datetime.datetime.now()
date_generated.replace(microsecond=0).isoformat(' ').partition('+')[0]
We can try something like below
import datetime
date_generated = datetime.datetime.now()
date_generated.replace(microsecond=0).isoformat(' ').partition('+')[0]
回答 9
我发现这是最简单的方法。
>>> t = datetime.datetime.now()
>>> t
datetime.datetime(2018, 11, 30, 17, 21, 26, 606191)
>>> t = str(t).split('.')
>>> t
['2018-11-30 17:21:26', '606191']
>>> t = t[0]
>>> t
'2018-11-30 17:21:26'
>>>
I found this to be the simplest way.
>>> t = datetime.datetime.now()
>>> t
datetime.datetime(2018, 11, 30, 17, 21, 26, 606191)
>>> t = str(t).split('.')
>>> t
['2018-11-30 17:21:26', '606191']
>>> t = t[0]
>>> t
'2018-11-30 17:21:26'
>>>
回答 10
我之所以使用它，是因为我可以更好地理解并记住它（日期时间格式也可以根据您的选择进行自定义）：-
import datetime
moment = datetime.datetime.now()
print("{}/{}/{} {}:{}:{}".format(moment.day, moment.month, moment.year,
moment.hour, moment.minute, moment.second))
This I use because I can understand and hence remember it better (and date time format also can be customized based on your choice) :-
import datetime
moment = datetime.datetime.now()
print("{}/{}/{} {}:{}:{}".format(moment.day, moment.month, moment.year,
moment.hour, moment.minute, moment.second))
