问题:从字符串创建Pandas DataFrame

为了测试某些功能,我想DataFrame从字符串创建一个。假设我的测试数据如下:

TESTDATA="""col1;col2;col3
1;4.4;99
2;4.5;200
3;4.7;65
4;3.2;140
"""

将数据读入熊猫的最简单方法是什么DataFrame

In order to test some functionality I would like to create a DataFrame from a string. Let’s say my test data looks like:

TESTDATA="""col1;col2;col3
1;4.4;99
2;4.5;200
3;4.7;65
4;3.2;140
"""

What is the simplest way to read that data into a Pandas DataFrame?


回答 0

一种简单的方法是使用StringIO.StringIO(python2)io.StringIO(python3)并将其传递给pandas.read_csv函数。例如:

import sys
if sys.version_info[0] < 3: 
    from StringIO import StringIO
else:
    from io import StringIO

import pandas as pd

TESTDATA = StringIO("""col1;col2;col3
    1;4.4;99
    2;4.5;200
    3;4.7;65
    4;3.2;140
    """)

df = pd.read_csv(TESTDATA, sep=";")

A simple way to do this is to use StringIO.StringIO (python2) or io.StringIO (python3) and pass that to the pandas.read_csv function. E.g:

import sys
if sys.version_info[0] < 3: 
    from StringIO import StringIO
else:
    from io import StringIO

import pandas as pd

TESTDATA = StringIO("""col1;col2;col3
    1;4.4;99
    2;4.5;200
    3;4.7;65
    4;3.2;140
    """)

df = pd.read_csv(TESTDATA, sep=";")

回答 1

分割法

data = input_string
df = pd.DataFrame([x.split(';') for x in data.split('\n')])
print(df)

Split Method

data = input_string
df = pd.DataFrame([x.split(';') for x in data.split('\n')])
print(df)

回答 2

交互式工作的快速简便解决方案是通过从剪贴板加载数据来复制和粘贴文本。

用鼠标选择字符串的内容:

复制数据以粘贴到Pandas数据框中

在Python Shell中使用 read_clipboard()

>>> pd.read_clipboard()
  col1;col2;col3
0       1;4.4;99
1      2;4.5;200
2       3;4.7;65
3      4;3.2;140

使用适当的分隔符:

>>> pd.read_clipboard(sep=';')
   col1  col2  col3
0     1   4.4    99
1     2   4.5   200
2     3   4.7    65
3     4   3.2   140

>>> df = pd.read_clipboard(sep=';') # save to dataframe

A quick and easy solution for interactive work is to copy-and-paste the text by loading the data from the clipboard.

Select the content of the string with your mouse:

Copy data for pasting into a Pandas dataframe

In the Python shell use read_clipboard()

>>> pd.read_clipboard()
  col1;col2;col3
0       1;4.4;99
1      2;4.5;200
2       3;4.7;65
3      4;3.2;140

Use the appropriate separator:

>>> pd.read_clipboard(sep=';')
   col1  col2  col3
0     1   4.4    99
1     2   4.5   200
2     3   4.7    65
3     4   3.2   140

>>> df = pd.read_clipboard(sep=';') # save to dataframe

回答 3

传统的可变宽度CSV无法将数据存储为字符串变量。尤其是在.py文件内部使用时,请考虑使用定宽管道分隔数据。各种IDE和编辑器可能都有一个插件,用于将管道分隔的文本格式化为整齐的表。

使用 read_csv

将以下内容存储在实用程序模块中,例如util/pandas.py。函数的文档字符串中包含一个示例。

import io
import re

import pandas as pd


def read_psv(str_input: str, **kwargs) -> pd.DataFrame:
    """Read a Pandas object from a pipe-separated table contained within a string.

    Input example:
        | int_score | ext_score | eligible |
        |           | 701       | True     |
        | 221.3     | 0         | False    |
        |           | 576       | True     |
        | 300       | 600       | True     |

    The leading and trailing pipes are optional, but if one is present,
    so must be the other.

    `kwargs` are passed to `read_csv`. They must not include `sep`.

    In PyCharm, the "Pipe Table Formatter" plugin has a "Format" feature that can 
    be used to neatly format a table.

    Ref: https://stackoverflow.com/a/46471952/
    """

    substitutions = [
        ('^ *', ''),  # Remove leading spaces
        (' *$', ''),  # Remove trailing spaces
        (r' *\| *', '|'),  # Remove spaces between columns
    ]
    if all(line.lstrip().startswith('|') and line.rstrip().endswith('|') for line in str_input.strip().split('\n')):
        substitutions.extend([
            (r'^\|', ''),  # Remove redundant leading delimiter
            (r'\|$', ''),  # Remove redundant trailing delimiter
        ])
    for pattern, replacement in substitutions:
        str_input = re.sub(pattern, replacement, str_input, flags=re.MULTILINE)
    return pd.read_csv(io.StringIO(str_input), sep='|', **kwargs)

非工作选择

以下代码无法正常运行,因为它在左侧和右侧都添加了一个空列。

df = pd.read_csv(io.StringIO(df_str), sep=r'\s*\|\s*', engine='python')

至于read_fwf,它实际上并没有使用太多read_csv接受和使用的可选kwarg 。因此,它根本不应该用于管道分隔的数据。

This answer applies when a string is manually entered, not when it’s read from somewhere.

A traditional variable-width CSV is unreadable for storing data as a string variable. Especially for use inside a .py file, consider fixed-width pipe-separated data instead. Various IDEs and editors may have a plugin to format pipe-separated text into a neat table.

Using read_csv

Store the following in a utility module, e.g. util/pandas.py. An example is included in the function’s docstring.

import io
import re

import pandas as pd


def read_psv(str_input: str, **kwargs) -> pd.DataFrame:
    """Read a Pandas object from a pipe-separated table contained within a string.

    Input example:
        | int_score | ext_score | eligible |
        |           | 701       | True     |
        | 221.3     | 0         | False    |
        |           | 576       | True     |
        | 300       | 600       | True     |

    The leading and trailing pipes are optional, but if one is present,
    so must be the other.

    `kwargs` are passed to `read_csv`. They must not include `sep`.

    In PyCharm, the "Pipe Table Formatter" plugin has a "Format" feature that can 
    be used to neatly format a table.

    Ref: https://stackoverflow.com/a/46471952/
    """

    substitutions = [
        ('^ *', ''),  # Remove leading spaces
        (' *$', ''),  # Remove trailing spaces
        (r' *\| *', '|'),  # Remove spaces between columns
    ]
    if all(line.lstrip().startswith('|') and line.rstrip().endswith('|') for line in str_input.strip().split('\n')):
        substitutions.extend([
            (r'^\|', ''),  # Remove redundant leading delimiter
            (r'\|$', ''),  # Remove redundant trailing delimiter
        ])
    for pattern, replacement in substitutions:
        str_input = re.sub(pattern, replacement, str_input, flags=re.MULTILINE)
    return pd.read_csv(io.StringIO(str_input), sep='|', **kwargs)

Non-working alternatives

The code below doesn’t work properly because it adds an empty column on both the left and right sides.

df = pd.read_csv(io.StringIO(df_str), sep=r'\s*\|\s*', engine='python')

As for read_fwf, it doesn’t actually use so many of the optional kwargs that read_csv accepts and uses. As such, it shouldn’t be used at all for pipe-separated data.


回答 4

最简单的方法是将其保存到临时文件,然后读取它:

import pandas as pd

CSV_FILE_NAME = 'temp_file.csv'  # Consider creating temp file, look URL below
with open(CSV_FILE_NAME, 'w') as outfile:
    outfile.write(TESTDATA)
df = pd.read_csv(CSV_FILE_NAME, sep=';')

创建临时文件的正确方法:如何在Python中创建tmp文件?

Simplest way is to save it to temp file and then read it:

import pandas as pd

CSV_FILE_NAME = 'temp_file.csv'  # Consider creating temp file, look URL below
with open(CSV_FILE_NAME, 'w') as outfile:
    outfile.write(TESTDATA)
df = pd.read_csv(CSV_FILE_NAME, sep=';')

Right way of creating temp file: How can I create a tmp file in Python?


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