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问题：在python中格式化“昨天”的日期
回答 0
回答 1
回答 2
回答 3
回答 4
回答 5

问题：在python中格式化“昨天”的日期

我需要MMDDYY在Python中以这种格式找到“昨天”的日期。

例如，今天的日期将这样表示：111009

我今天可以轻松完成此操作，但是在“昨天”自动执行此操作有麻烦。

点击查看英文原文

I need to find “yesterday’s” date in this format MMDDYY in Python.

So for instance, today’s date would be represented like this: 111009

I can easily do this for today but I have trouble doing it automatically for “yesterday”.

回答 0

用 datetime.timedelta()

>>> from datetime import date, timedelta
>>> yesterday = date.today() - timedelta(days=1)
>>> yesterday.strftime('%m%d%y')
'110909'
点击查看英文原文

Use datetime.timedelta()

>>> from datetime import date, timedelta
>>> yesterday = date.today() - timedelta(days=1)
>>> yesterday.strftime('%m%d%y')
'110909'

回答 1

from datetime import datetime, timedelta

yesterday = datetime.now() - timedelta(days=1)
yesterday.strftime('%m%d%y')
点击查看英文原文 
from datetime import datetime, timedelta

yesterday = datetime.now() - timedelta(days=1)
yesterday.strftime('%m%d%y')

回答 2

这应该做您想要的：

import datetime
yesterday = datetime.datetime.now() - datetime.timedelta(days = 1)
print yesterday.strftime("%m%d%y")
点击查看英文原文

This should do what you want:

import datetime
yesterday = datetime.datetime.now() - datetime.timedelta(days = 1)
print yesterday.strftime("%m%d%y")

回答 3

所有答案都是正确的，但是我想提到时间增量接受否定论点。 

>>> from datetime import date, timedelta
>>> yesterday = date.today() + timedelta(days=-1)
>>> print(yesterday.strftime('%m%d%y')) #for python2 remove parentheses
点击查看英文原文

all answers are correct, but I want to mention that time delta accepts negative arguments. 

>>> from datetime import date, timedelta
>>> yesterday = date.today() + timedelta(days=-1)
>>> print(yesterday.strftime('%m%d%y')) #for python2 remove parentheses

回答 4

我可以将其设置为更具国际性，并根据国际标准设置日期格式，而不是在美国常见的怪异的月-日-年格式中吗？

from datetime import datetime, timedelta

yesterday = datetime.now() - timedelta(days=1)
yesterday.strftime('%Y-%m-%d')
点击查看英文原文

Could I just make this somewhat more international and format the date according to the international standard and not in the weird month-day-year, that is common in the US?

from datetime import datetime, timedelta

yesterday = datetime.now() - timedelta(days=1)
yesterday.strftime('%Y-%m-%d')

回答 5

扩展克里斯给出的答案

如果您想以特定格式将日期存储在变量中，就我所知，这是最短，最有效的方法

>>> from datetime import date, timedelta                   
>>> yesterday = (date.today() - timedelta(days=1)).strftime('%m%d%y')
>>> yesterday
'020817'

如果您希望将其作为整数（可能会有用）

>>> yesterday = int((date.today() - timedelta(days=1)).strftime('%m%d%y'))
>>> yesterday
20817
点击查看英文原文

To expand on the answer given by Chris

if you want to store the date in a variable in a specific format, this is the shortest and most effective way as far as I know

>>> from datetime import date, timedelta                   
>>> yesterday = (date.today() - timedelta(days=1)).strftime('%m%d%y')
>>> yesterday
'020817'

If you want it as an integer (which can be useful)

>>> yesterday = int((date.today() - timedelta(days=1)).strftime('%m%d%y'))
>>> yesterday
20817
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