问题:Django:登录后重定向到上一页

我正在尝试建立一个简单的网站,其登录功能与SO上的登录功能非常相似。该用户应该能够以匿名用户身份浏览该网站,并且每个页面上都会有一个登录链接。当单击登录链接时,用户将被带到登录表单。成功登录后,应将用户带回到他首先单击登录链接的页面。我猜想我必须以某种方式将当前页面的url传递给处理登录表单的视图,但是我真的无法使其正常工作。

编辑:我想通了。我通过将当前页面作为GET参数传递来链接到登录表单,然后使用“下一个”重定向到该页面。谢谢!

编辑2:我的解释似乎不清楚,所以这里要求的是我的代码:假设我们在页面foo.html上,并且尚未登录。现在,我们希望在foo.html上有一个链接,该链接登录。我们可以在那里登录,然后将其重定向回foo.html。foo.html上的链接如下所示:

      <a href='/login/?next={{ request.path }}'>Login</a> 

现在,我编写了一个自定义登录视图,看起来像这样:

def login_view(request):
   redirect_to = request.REQUEST.get('next', '')
   if request.method=='POST':
      #create login form...
      if valid login credentials have been entered:
         return HttpResponseRedirect(redirect_to)  
   #...
   return render_to_response('login.html', locals())

还有login.html中的重要一行:

<form method="post" action="./?next={{ redirect_to }}">

是的,就这样,希望可以弄清楚。

I’m trying to build a simple website with login functionality very similar to the one here on SO. The user should be able to browse the site as an anonymous user and there will be a login link on every page. When clicking on the login link the user will be taken to the login form. After a successful login the user should be taken back to the page from where he clicked the login link in the first place. I’m guessing that I have to somehow pass the url of the current page to the view that handles the login form but I can’t really get it to work.

EDIT: I figured it out. I linked to the login form by passing the current page as a GET parameter and then used ‘next’ to redirect to that page. Thanks!

EDIT 2: My explanation did not seem to be clear so as requested here is my code: Lets say we are on a page foo.html and we are not logged in. Now we would like to have a link on foo.html that links to login.html. There we can login and are then redirected back to foo.html. The link on foo.html looks like this:

      <a href='/login/?next={{ request.path }}'>Login</a> 

Now I wrote a custom login view that looks somewhat like this:

def login_view(request):
   redirect_to = request.REQUEST.get('next', '')
   if request.method=='POST':
      #create login form...
      if valid login credentials have been entered:
         return HttpResponseRedirect(redirect_to)  
   #...
   return render_to_response('login.html', locals())

And the important line in login.html:

<form method="post" action="./?next={{ redirect_to }}">

So yeah thats pretty much it, hope that makes it clear.


回答 0

您无需为此额外查看,该功能已内置。

首先,每个具有登录链接的页面都需要知道当前路径,最简单的方法是将请求上下文前置变量添加到settings.py(默认为前四个),然后在每个请求中都可以使用请求对象:

settings.py:

TEMPLATE_CONTEXT_PROCESSORS = (
    "django.core.context_processors.auth",
    "django.core.context_processors.debug",
    "django.core.context_processors.i18n",
    "django.core.context_processors.media",
    "django.core.context_processors.request",
)

然后添加您想要“登录”链接的模板:

base.html:

<a href="{% url django.contrib.auth.views.login %}?next={{request.path}}">Login</a>

这会将GET参数添加到登录页面,该参数指向当前页面。

登录模板可以像下面这样简单:

registration / login.html:

{% block content %}
<form method="post" action="">
  {{form.as_p}}
<input type="submit" value="Login">
</form>
{% endblock %}

You do not need to make an extra view for this, the functionality is already built in.

First each page with a login link needs to know the current path, and the easiest way is to add the request context preprosessor to settings.py (the 4 first are default), then the request object will be available in each request:

settings.py:

TEMPLATE_CONTEXT_PROCESSORS = (
    "django.core.context_processors.auth",
    "django.core.context_processors.debug",
    "django.core.context_processors.i18n",
    "django.core.context_processors.media",
    "django.core.context_processors.request",
)

Then add in the template you want the Login link:

base.html:

<a href="{% url django.contrib.auth.views.login %}?next={{request.path}}">Login</a>

This will add a GET argument to the login page that points back to the current page.

The login template can then be as simple as this:

registration/login.html:

{% block content %}
<form method="post" action="">
  {{form.as_p}}
<input type="submit" value="Login">
</form>
{% endblock %}

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